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Alexus [3.1K]
3 years ago
15

Is it true that newtons laws of universal gravitation states that every object in the universe attracts every other object

Physics
1 answer:
alexandr402 [8]3 years ago
6 0

Newton's laws clearly state that his laws talk about force and that   every object persists in it's state of rest or uniform motion in a straight line unless it is compelled to change the state that it is in. SO in that hence i would have to say that the statement is false.

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According to the ideal gas law, a 1.074 mol sample of oxygen gas in a 1.746 L container at 267.6 K should exert a pressure of 13
luda_lava [24]

Answer:

% differ  1.72%

Explanation:

given data:

P_ideal = 13.51 atm

n = 1.074 mol

V = 1.746 L

T = 267.6 K

According to ideal gas law we have

(P+ \frac{n^2 *a}{v^2}) (V - nb) = nRT

(P+ (\frac{1.074^2 *1.360}{1.746^2})) (1.746 - 1.074*3.183*10^{-2}) = 1.074*0.0821*267.6

(P+0.514)(1.711) = 23.59

P_v = 13.276 atm

% differ = \frac{ P_I - P_v}{P_I} *100

             = \frac{13.51 - 13.27}{13.51} *100

             = 1.72%

3 0
3 years ago
Look around the room you are in. Name
kozerog [31]

Answer:

A wire,rubber

Explanation:

yes

3 0
3 years ago
Read 2 more answers
A scientist who wants to study the affects of fertilizer on plants sets up an experiment. Plant A gets no fertilizer, Plant B ge
Solnce55 [7]

Answer: Plant A

Explanation: The control group is participants who do not receive the experimental treatment.

8 0
3 years ago
Mike walks 200 km in 6 hours.he then walks another 100km in 4 hours .what is his average speed?
kolbaska11 [484]

Average speed is defined as the ratio of total distance covered in total given time

speed = \frac{distance}{time}

here we know that total distance that man moved is

d_1 = 200 km

d_2 = 100 km

so total distance is

d = d_1 + d_2

d = 200 km + 100 km

d = 300 km

now here total time of the motion is

t_1 = 6 hours

t_2 = 4 hours

total time will be given as

t = t_1 + t_2

t = 6 + 4 = 10 hours

now by above formula

v_{avg} = \frac{300}{10}

v_{avg} = 30 km/h

so his average speed is 30 km/h

8 0
3 years ago
What is the energy of a photon whose frequency is 6.0 x 10^20?
omeli [17]

Answer:

3.75 MeV

Explanation:

The energy of the photon can be given in terms of frequency as:

E = h * f

Where h = Planck's constant

The frequency of the photon is 6 * 10^20 Hz.

The energy (in Joules) is:

E = 6.63 x10^(-34) * 6 * 10^(20)

E = 39.78 * 10^(-14) J = 3.978 * 10^(-13) J

We are given that:

1 eV = 1.06 * 10^(-19) Joules

This means that 1 Joule will be:

1 J = 1 / (1.06 * 10^(-19)

1 J = 9.434 * 10^(18) eV

=> 3.978 * 10^(-13) J = 3.978 * 10^(-13) * 9.434 * 10^(18) = 3.75 * 10^(6) eV

This is the same as 3.75 MeV.

The correct answer is not in the options, but the closest to it is option C.

6 0
2 years ago
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