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3 years ago

A 4-watt night light is left on for 8 hours each night. How much work dies it do per night

1 answer:

4 0

The light bulb doesn't do any "work" ... it doesn't exert force,
or maintain a force through a distance. It does, however,
dissipate energy, in the form of heat and light.

The quantity of energy that it dissipates is ...

(4 watts) x (8 hours) x (3600 sec/hour) x (1 joule/watt-sec)

= (4 x 8 x 3600) joules = 115,200 joules .

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lawyer [7]

In astronomy circumpolar constellations are those ones which never set from viewer's perspective like ursa minor, cassiopiea etc.

Because of the rotation of the Earth and its orbit around the Sun, we divide the stars and constellations into two groups. Some stars and constellations never rise nor set, and they are called circumpolar. All the rest are divided into seasonal stars and constellations. Which stars and constellations will be circumpolar and which seasonal depends on your latitude.

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4 years ago

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Answer:

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3 years ago

Thanks + BRAINLIST <br><br> Please need correct answer asappp

garik1379 [7]

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3 years ago

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According to Newton's Brd Law, an object's momentum depends on it's velocity and mass, 4 dog-sled teams

Kryger [21]

Answer:

Team A has the greatest momentum

Explanation:

The momentum of an object is a vector quantity given by

$p=mv$

where

m is the mass of the object

v is its velocity

In this problem, we have to compare the momenta of the different sleds.

We have:

A) Sled Team A 48 kg moving at 10m/s:

m = 48 kg

v = 10 m/s

p = (48)(10) = 480 kg m/s

B) Sled Team B 14 kg moving at 18m/s

m = 14 kg

v = 18 m/s

p = (14)(18) = 252 kg m/s

C) Sled Team C 28 kg moving at 12m/s

m = 28 kg

v = 12 m/s

p = (28)(12) = 336 kg m/s

D) Sled Team D 22 kg moving at 12m/s

m = 22 kg

v = 12 m/s

p = (22)(12) = 264 kg m/s

So, team A has the greatest momentum.

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3 years ago

A positive test charge of 8.5 × 10 negative 7 Columbus experiences a force of 4.1 × 10 negative 1 N calculate the electric field

Sophie [7]

Explanation:

direction of electric field is same as that of force experienced by the test charge

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