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Sladkaya [172]
3 years ago
14

Where should an object be placed in front of a concave mirror’s principal axis to form an image that is real, inverted, larger t

han the object, and farther from the mirror than the object is?
Physics
2 answers:
Charra [1.4K]3 years ago
7 0
If the object is kept in between the principle axis and the focus but some what nearer to the focus then we will get the enlarge,erect,and real image.

Alja [10]3 years ago
6 0

Answer:

At focus.

Explanation:

When the object is placed at the focus of a concave mirror, the image will form at infinity. The formed image is real and inverted and its size is highly enlarged.

When the object is placed between the pole and the focus, the image will formed behind the mirror. The formed image is virtual and erect and its size is enlarged. This is the only case when the formed image is virtual and erect.

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What is the difference in Neil Armstrong’s weight on the moon and on earth? Neils mass is 160kg including his spacesuit and back
Len [333]

Explanation:

Given parameters:

Mass of Neil Armstrong = 160kg

Gravitational pull of earth = 10N/kg

Moon's pull = 17% of the earth's pull

Unknown:

Difference between Armstrong's weight on moon and on earth.

Solution:

To find the weight,

   Weight = mass x acceleration due to gravity = mg

Moon's gravitational pull = 17% of the earth's pull = 17% x 10 = 1.7N/kg

Weight on moon = 160 x 1.7 = 272N

Weight on earth = 160 x 10 = 1600N

The difference in weight = 1600 - 272 = 1328N

The weight of Armstrong on earth is 1328N more than on the moon.

Learn more:

Weight and mass brainly.com/question/5956881

#learnwithBrainly

3 0
2 years ago
Is it possible for an object to have a charge of 4.8x10-9 C? Why or why not?
Gelneren [198K]
I have absolutely no clue
3 0
3 years ago
Juan is receiving bills from the hospital even though his insurance company said his procedure would be covered in full. What st
BaLLatris [955]

==> Jot down notes before and after making each call, and avoid calling during business hours when people are busy.

==> Save all emails and bills, and follow up to make sure people did what they said they would do.

5 0
3 years ago
suppose that you look into a photometer's eyepiece and the fluorescent disks appear to be equal in intensity. If the distance be
d1i1m1o1n [39]
Use the Inverse square law, Intensity (I) of a light is inversely proportional to the square of the distance(d).

I=1/(d*d)

Let Intensity for lamp 1 is L1 distance be D1 so on, L2 D2 for Intensity for lamp 2 and its distance.

L1/L2=(D2*D2)/(D1*D1)

L1/15=(200*200)/(400*400)
L1=15*0.25
L1=3.75 <span>candela</span>

7 0
3 years ago
A 1.0 kg rock is thrown straight upward with an initial speed of 8.0 m/s. What is its speed
Ronch [10]

Answer:5.7m/s

Explanation:

Mass=1kg

Initial velocity=u=8m/s

height=h=1.6m

Final velocity =v

Acceleration due to gravity=g=9.8m/s^2

v^2=u^2-2xgxh

v^2=8^2-2x9.8x1.6

v^2=8x8-2x9.8x1.6

v^2=64-31.36

v^2=32.64

Take the square root of both sides

√(v^2)=√(32.64)

v=5.7

Speed at the height of 1.6m is 5.7m/s

8 0
3 years ago
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