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konstantin123 [22]
3 years ago
9

Find the total electric charge of 2.5 kg of electrons. Express your answer using two significant figures.

Physics
1 answer:
zimovet [89]3 years ago
4 0

Answer : The total electric charge of electrons is, -4.4\times 10^{11}C

Explanation:

Answer : The number of electrons transferred are, 4.68\times 10^{20}

Explanation :

First we have to calculate the number of electrons.

Number of electrons = \frac{\text{Total mass of electrons}}{\text{Mass of one electron}}

Mass of 1 electron = 9.1\times 10^{-31}kg

Total mass of electron = 2.5 kg

Number of electrons = \frac{2.5kg}{9.1\times 10^{-31}kg}

Number of electrons = 2.75\times 10^{30}

Now we have to calculate the total electric charge of electrons.

Formula used :

Q=ne\\\\n=\frac{Q}{e}

where,

n = number of electrons transferred = 2.75\times 10^{30}

Q = charge on electrons = ?

e = charge on 1 electron = -1.602\times 10^{-19}C

Now put all the given values in the above formula, we get:

2.75\times 10^{30}=\frac{Q}{-1.602\times 10^{-19}C}

Q=-4.4\times 10^{11}C

Thus, the total electric charge of electrons is, -4.4\times 10^{11}C

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Answer:

1.08 * 10^{14} J

Explanation:

Energy and mass are related by the famous equation developed by Albert Einstein:

E = mc^2

where m = mass and c = speed of light

This equation explains that an object with very small mass can produce a large amount of energy in reactions such as a nuclear reaction.

Hence, the energy produced by the explosion of a Plutonium bomb containing 3.6 grams of matter is:

E = 3.6 * 10^{-3} * (3 * 10^8)^2

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3 0
3 years ago
An RC circuit takes t = 2.5 ms to charge to 35% of its full charge after it weas connected to a battery, What is the total time
marin [14]

Answer: time taken to charge to 95%

t = -5.80[ln(1-0.95)]

t = 17.38ms

Explanation:

For an RC Charging circuit

Where Vs

Vc = Vs (1 - e^(-t/RC))

Vc/Vs = 1 - e^(-t/RC)

-t/RC = ln(1 - Vc/Vs)

t = -RC[ln(1 - Vc/Vs)] and RC = k = -t/ln(1 - Vc/Vs)

Where ;

Vc = voltage across the capacitor

Vs = voltage supply

t = charging time = 2.5ms

k = RC = time constant.

Vc/Vs = 0.35

To calculate the time constant k;

k = -t/ln(1- Vc/Vs)

k = -2.5/ln(1-0.35)

k = 5.80ms

time taken to charge to 95%

t = -5.80[ln(1-0.95)]

t = 17.38ms

4 0
3 years ago
Which of the following describes gamma rays?
Anarel [89]

Answer: short wavelength, high frequency

Explanation:

Gamma rays are highly energetic electromagnetic waves. High energy implies high frequency.

E = h ν

h is the Planck's constant, ν is the frequency.

For electromagnetic radiation, frequency is inversely proportional to wavelength. Thus, gamma rays have high frequency but short wavelength.

The frequency of gamma rays is greater than 10¹⁹ Hz and wavelength is less 10⁻¹² m.

3 0
2 years ago
Read 2 more answers
The product of voltage times amperage is known as what?
Usimov [2.4K]

Answer:

Power=V*I which corresponds to the second option shown: "voltage times amperage"

Explanation:

The electric power is the work done to move a charge Q across a given difference of potential V per unit of time.

Since such electrical work is the product of the potential difference V times the charge that moves through that potential, and this work is to be calculated by the unit of time, we need to divide the product by time (t) which leads to the following final simple equation

Power=\frac{V\,Q}{t} =V\,\frac{Q}{t} = V\, I

5 0
3 years ago
A sled is accelerating down a hill at a rate of 1 m s2 . If the mass of the sled is suddenly cut in half and the net force on th
mihalych1998 [28]
We have that F=ma from the 2nd Newton law where F is the force, m is the mass and a is the acceleration. Suppose we have that F' is the new force and m' is the new mass. Then, we have that a'=F'/m' still, by rearranging Newton's law. We are given that F'=2F and m'=m/2. Hence,
a'= \frac{2F}{ \frac{m}{2} } = \frac{4F}{m} = 4\frac{F}{m}
But now, we have from F=ma, that a=F/m and we are given that a=1m/s^2.
We can substitute thus, a'=4a=4*1m/s^2=4m/s^2.
4 0
2 years ago
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