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dlinn [17]
3 years ago
7

An ideal air-filled parallel-plate capacitor has round plates and carries a fixed amount of equal but opposite charge on its pla

tes. all the geometric parameters of the capacitor (plate diameter and plate separation) are now doubled. if the original energy density between the plates was u0, what is the new energy density?
Physics
1 answer:
Oxana [17]3 years ago
7 0
<span>When two point charges are a distance d apart, the electric force that each one feels from the other has magnitude F. In order to make this force twice as strong, the distance would have to be changed to When two point charges are a distance d apart, the electric force that each one feels from the other has magnitude F. In order to make this force twice as strong, the distance would have to be changed to d/âš2</span>
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Consider the two-body situation at the right. A 3.50x103-kg crate (m1) rests on an inclined plane and is connected by a cable to
4vir4ik [10]

Answer:a=2.42 m/s^2

Explanation:

Given

mass m_1=3.50\times 10^{3} kg

m_2=1.00\times 10^{3} kg

\theta(inclination)=30^{\circ}

\mu =0.21

Let T be the tension in the rope

From Diagram

m_1g\sin \theta -T-f_r=m_1a-----------------1

where f_r=friction\ force

f_r=\mu m_g\cos \theta

For block m_2

T=m_2a-----------2

From 1 & 2

m_1g\sin \theta -m_2a-\mu m_1g\cos \theta =m_1a

m_1g(\sin \theta -\mu \cos \theta )=(m_1+m_2)a

\frac{9.8\times 3.5\times 10^3}{4.5\times 10^3}(0.5-\0.21\cos 30)=4.5a

a=2.42 m/s^2

4 0
4 years ago
A cement factory emits 900 kilograms of CO2 to produce 1,000 kilograms of cement. A fully grown tree removes six kilograms of CO
Ierofanga [76]
Since the factory will be producing 100,000 kilograms of cement, using the relation 1000 kg of cement = 900 kg of CO2, then the factory will be emitting 90,000 kg of CO2 at the same time. To counteract the emission, a tree can remove 6 kg of CO2 per day. Dividing 90,000 kg by 6 kg to know the number of trees, we need 15000 trees to counter the emission. Since 1 acre of land holds 200 trees, we need 75 acres of land to hold the 15000 trees.
3 0
4 years ago
An airline employee tosses two suitcases in rapid succession with a horizontal velocity of 7.2 ft/s onto a 50-lb baggage carrier
zalisa [80]

Answer:

m₁ = 70 lb

Explanation:

Here we will use the law of conservation of momentum:

m₁u₁ + m₂u₂ + m₃u₃ = m₁v₁ + m₂v₂ + m₃v₃

where,

m₁ = mass of first suitcase = ?

m₂ = mass of second suitcase = 30 lb

m₃ = mass of baggage carrier = 50 lb

u₁ = initial speed of first suitcase = 7.2 ft/s

u₂ = initial speed of second suitcase = 7.2 ft/s

u₃ = initial speed of baggage carrier = 0 ft/s

v₁ = Final speed of first suitcase = 4.8 ft/s

v₂ = Final speed of second suitcase = 4.8 ft/s

v₃ = Final speed of baggage carrier = 4.8 ft/s

because after collision all three will have same speed

Therefore,

(m₁)(7.2 ft/s) + (30 lb)(7.2 ft/s) + (50 lb)(0 ft/s) = (m₁)(4.8 ft/s) + (30 lb)(4.8 ft/s) + (50 lb)(4.8 ft/s)

(m₁)(7.2 ft/s) + (216 lb ft/s) + (0 lb ft/s) = (m₁)(4.8 ft/s) + (144 lb ft/s) + (240 lb ft/s)

(m₁)(7.2 ft/s) - (m₁)(4.8 ft/s) = 168 lb ft/s

m₁ = (168 lb ft/s)/(2.4 ft/s)

<u>m₁ = 70 lb</u>

6 0
3 years ago
28.25 mL, three signicant digits
Mazyrski [523]

Answer:3) variable affinities (stickiness) for something it is running past. Physical ... -measurement number (significant digits) unit (such as inches) -Significant ... Mass 1 oz. 28.25 g. Relations Between English and Metric Units Mass 1 dram. 1.772 g ... -graduated cylinder has an error of about 1% (± 0.1 mL in 10 mL). -Volumetric

Explanation:

3 0
3 years ago
Read 2 more answers
Xavier throws a tennis ball to his friend Olaf at a 20° angle relative to the ground with an initial velocity of 18 m/s. The ten
Svetllana [295]

Ball is thrown at an angle of 20 degree with velocity 18 m/s

so first we will find the two components of the velocity

v_x = 18 cos20

v_x = 16.91 m/s

similarly for other component

v_y = 18 sin20

v_y = 6.16 m/s

now the ball will cover horizontal distance of 30 m till it reach to other player

so here we can use the formula of time

x = v_x * t

30 = 16.91 * t

t = \frac{30}{16.91}

t = 1.77 s

so it will take 1.77 s to reach the other player

3 0
3 years ago
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