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FromTheMoon [43]
3 years ago
11

Write the fraction as a percent: 11/50. (Simplify your Answer.)

Mathematics
1 answer:
s2008m [1.1K]3 years ago
8 0
To find the percent of a fraction you have to find the decimal first. 11/50=.22
To turn a decimal into a fraction you put the decimal two places back;22.00. The answer should be 22%
You might be interested in
Factor 64-112w+49w^2
photoshop1234 [79]
49w² -112w + 64
first, you have to find 2 numbers that add up to equal -112, but also multiply together to get a product of 3136 (49 * 64)

two numbers that add to -112 and multiply to equal 3136 is -56 and -56
we can add them into the equation by putting them in for -112x

49w²-56w-56w+64

we now look at what the first 2 numbers have in common and what the last two numbers have in common
49w² and -56w both have w and 7 in common so we can divide 7w
7w(7w -8)
-56w and 64 both have -8 in common so we can divide by -8
-8(7w-8)
now we take the 2 numbers on the outside and bring down the numbers in the brackets

(7w-8)(7w-8)
(7w-8)²

7 0
3 years ago
What are the solutions to the quadratic equation x^2-16=0
Paha777 [63]

Answer:

x = ±4

Step-by-step explanation:

Hi there!

x^2-16=0

Move 16 to the other side

x^2=16

Take the square root of both sides

\sqrt{x^2}=\sqrt{16}\\x=\pm4

I hope this helps!

3 0
2 years ago
PLZ help geometry proof. Will give Brainlyiest I’ve posted question 3 times so you can get triple the points
levacccp [35]

Answer:

The two column proof can be presented as follows;

Statement                     {}                   Reason

1. p║q                    {}                        Given

∠1 ≅ ∠11

2. ∠1 ≅ ∠9                     {}               Corresponding angles on parallel lines

3. ∠9 ≅ ∠11                    {}               Transitive property of equality

4. a║b                    {}                       Corresponding angles on parallel lines are congruent

Step-by-step explanation:

The statements in the two column proof can be explained as follows;

Statement                     {}                Explanation

1. p║q                    {}                        Given

∠1 ≅ ∠11

2. ∠1 ≅ ∠9                     {}               Corresponding angles on parallel lines crossed by a common transversal are congruent

3. ∠9 ≅ ∠11                    {}               Transitive property of equality

Given that ∠1 ≅ ∠11 and we have that ∠1 ≅ ∠9, then we can transit the terms between the two expressions to get, ∠9 ≅ ∠11 which is the same as ∠11 ≅ ∠9

4. a║b                    {}                       Corresponding angles on parallel lines are congruent

Whereby we now have ∠9 which is formed by line a and the transversal line q, is congruent to ∠11 which is formed by line b and the common transversal line q, and both ∠9 and ∠11 occupy corresponding locations on lines a and b respectively which are crossed by the transversal, line q, then lines a and b are parallel to each other or a║b.

4 0
2 years ago
Thank you in advance for your help!
Lelechka [254]
I appreciate it too , I had a major problem solving that one.
5 0
3 years ago
I need someone who is great with trig to help me with some Qs on my profile
Svetradugi [14.3K]

Answer:

Ok.

Step-by-step explanation:

  Since I will help you, can I get brainliest?

8 0
3 years ago
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