49w² -112w + 64
first, you have to find 2 numbers that add up to equal -112, but also multiply together to get a product of 3136 (49 * 64)
two numbers that add to -112 and multiply to equal 3136 is -56 and -56
we can add them into the equation by putting them in for -112x
49w²-56w-56w+64
we now look at what the first 2 numbers have in common and what the last two numbers have in common
49w² and -56w both have w and 7 in common so we can divide 7w
7w(7w -8)
-56w and 64 both have -8 in common so we can divide by -8
-8(7w-8)
now we take the 2 numbers on the outside and bring down the numbers in the brackets
(7w-8)(7w-8)
(7w-8)²
Answer:
x = ±4
Step-by-step explanation:
Hi there!

Move 16 to the other side

Take the square root of both sides

I hope this helps!
Answer:
The two column proof can be presented as follows;
Statement
Reason
1. p║q
Given
∠1 ≅ ∠11
2. ∠1 ≅ ∠9
Corresponding angles on parallel lines
3. ∠9 ≅ ∠11
Transitive property of equality
4. a║b
Corresponding angles on parallel lines are congruent
Step-by-step explanation:
The statements in the two column proof can be explained as follows;
Statement
Explanation
1. p║q
Given
∠1 ≅ ∠11
2. ∠1 ≅ ∠9
Corresponding angles on parallel lines crossed by a common transversal are congruent
3. ∠9 ≅ ∠11
Transitive property of equality
Given that ∠1 ≅ ∠11 and we have that ∠1 ≅ ∠9, then we can transit the terms between the two expressions to get, ∠9 ≅ ∠11 which is the same as ∠11 ≅ ∠9
4. a║b
Corresponding angles on parallel lines are congruent
Whereby we now have ∠9 which is formed by line a and the transversal line q, is congruent to ∠11 which is formed by line b and the common transversal line q, and both ∠9 and ∠11 occupy corresponding locations on lines a and b respectively which are crossed by the transversal, line q, then lines a and b are parallel to each other or a║b.
I appreciate it too , I had a major problem solving that one.
Answer:
Ok.
Step-by-step explanation:
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