Answer:
Part A
Kp = 3.4 x 10⁴
Part B
Kp = 2.4 x 10⁻¹⁴
Part C
Kp = 1.2 x 10⁹
Explanation:
2PH₃(g) + As₂(g) ⇌ 2 AsH₃(g) + P₂(g) Kp = 2.9 x 10⁻⁵
Kp = [AsH₃]²[P₂]/[PH₃]²[As] = 2.9 x 10⁻⁵
Part A
it is the inverse of the equilibrium given
Kp(A) = 1/ Kp = 1 / 2.9 x 10⁻⁵ = 3.4 x 10⁴
Part B
Is the equilibrium where the coefficients have been multiplied by 3,
Kp(B) = ( Kp )³ = ( 2.9 x 10⁻⁵ )³ = 2.4 x 10⁻¹⁴
Part C
This is the reverse equilibrium multipled by 2.
Kp(C) = ( 1/Kp)² = ( 1/ 2.9 x 10⁻⁵ )² = 1.2 x 10⁹
find mol of N2 present using gas law equation
PV = nRT
P = pressure = 688/760 = 0.905 atm.
V = 100mL = 0.1L
n = ???
R = 0.082057
T = 565+273 = 838
Substitute:
0.905*0.1 = n*0.082057*838
n = 0.0905 / 68.76
n = 0.00132 mol N2
Molar mass N2 = 28 g/mol
0.00132 mol = 0.00132*28 = 0.037g N2 gas
You can predict it based of the electronegativity
If you are asking which is the most abundant, Uranium-238 is
Cu + S ---> CuS
by reaction 1 mol 1 mol
from the problem 0.25 mol 0.25 mol
0.25 mol Cu
