Help with a chem question?

1. An atom that has an outer shell that is NOT full is (more likely OR less likely) to be reactive than an atom that has a full

Simora [160]

It would be more likely because it is considered unstable more reactive.

5 0

4 years ago

Based on the law of conservation of mass, which of the following statements is correct? Matter is neither created nor destroyed.

Dmitrij [34]

The first statement (Matter is neither created nor destroyed) is correct.

The second statement would violate the law of conservation of mass (I will refer to this as LCM), as it would mean matter can "flow" into the universe, but not out, meaning the total matter will never be less than it was before.

The third statement violates LCM because it means matter is created during a reaction, which is not true.

The last statement violates LCM because it means matter is lost during a reaction, which is not true.

7 0

3 years ago

Calculate Ecell for the following electrochemical cell at 25 ºCPt (s) | H2 (g, 1.00 atm) | H+ (aq, 1.00 M) || Sn2+ (aq, 0.350 M)

katrin2010 [14]

Answer: The electrode potential of the cell is 0.093 V

Explanation:

The given chemical cell follows:

$Pt(s)|H_2(g,1atm)|H^+(aq,1.00M)||Sn^{4+}(aq,0.020M)|Sn^{2+}(aq.,0.350M)|Pt(s)$

Oxidation half reaction: $H_2(g,1atm)\rightarrow 2H^{+}(aq,1.0M)+2e^-;E^o_{2H^{+}/H_2}=0.0V$

Reduction half reaction: $Sn^{4+}(aq,0.020M)+2e^-\rightarrow Sn^{2+(aq.,0.350M);E^o_{Sn^{4+}/Sn^{2+}}=0.13V$

Net cell reaction:

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=0.13-(0.0)=0.13V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[H^{+}]^2[Sn^{2+}]}{[Sn^{4+}]}$

where,

$E_{cell}$ = electrode potential of the cell = ? V

$E^o_{cell}$ = standard electrode potential of the cell = +0.13 V

n = number of electrons exchanged = 2

$[H^{+}]=1.00M$

$[Sn^{2+}]=0.350M$

$[Sn^{4+}]=0.020M$

Putting values in above equation, we get:

$E_{cell}=0.13-\frac{0.059}{2}\times \log(\frac{(1.0)^2\times 0.350}{0.020})$

$E_{cell}=0.093V$

Hence, the electrode potential of the cell is 0.093 V

3 0

4 years ago

Define what natural gas is, explain how it forms, and what it is used for today.

natta225 [31]

Answer:

is a naturally occurring hydrocarbon gas mixture consisting primarily of methane, but commonly including varying amounts of other higher alkanes, and sometimes a small percentage of carbon dioxide, nitrogen, hydrogen sulfide, or helium.

It is formed when layers of decomposing plant and animal matter are exposed to intense heat and pressure under the surface of the Earth over millions of years. The energy that the plants originally obtained from the sun is stored in the form of chemical bonds in the gas

for heating, cooking, and electricity generation. It is also used as a fuel for vehicles and as a chemical feedstock in the manufacture of plastics and other commercially important organic chemicals.

7 0

3 years ago

An object has a mass of 33g and a volume of 11ml. What is it's density?

astra-53 [7]

Answer:

3g/ml

Explanation:

Density = $\frac{33g}{11ml}$

33 divided by 11 = 3

5 0

4 years ago