17th Century
In 1661 he founded a scientific society which later became known as the Royal Society of England. Traditional Chemistry - The Mid 17th Century to mid 19th Century By this time scientists were using the "modern method" of discovery by testing theories with experiments.
Answer:
The charged particle will follow a circular path.
Explanation:
The magnetic force exerted on the charged particle due to the magnetic field is given by:

where
q is the charge
v is the velocity of the particle
B is the magnetic field
is the angle between v and B
In this problem, the velocity is perpendicular to the magnetic field, so
and the force is simply

Moreover, the force is perpendicular to both B and v, according to the right-hand rule. Therefore, we have:
- a force that is always perpendicular to the velocity, v
- a force which is constant in magnitude (because the magnitude of v or B does not change)
--> this means that the force acts as a centripetal force, so it will keep the charged particle in a uniform circular motion. So, the correct answer is
The charged particle will follow a circular path.
<h2>
The seagull's approximate height above the ground at the time the clam was dropped is 4 m</h2>
Explanation:
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Time, t = 3 s
Substituting
s = ut + 0.5 at²
s = 0 x 3 + 0.5 x 9.81 x 3²
s = 44.145 m
The seagull's approximate height above the ground at the time the clam was dropped is 4 m
Answer:
Correct Answer: Option B
Explanation
V.R = 1sinθ=1sin30=21sinθ=1sin30=2
M.A = E×V.R100=50×2100=1E×V.R100=50×2100=1
Effort = loadM.A=1201=120N
Answer:
N = 2490 N
Explanation:
Determine the upward force exerted by the horizontal platform on the box as it is lowered.
It is given that,
Mass of a box, m = 300 kg
Starting from rest at time t = 0 seconds, the box is lowered with a downward acceleration of 1.5 m/s².
It is assumed to find the upward force exerted by the horizontal platform on the box. It is given by :
mg-N=ma

So, the normal force is 2490 N.