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Answer:
1.23 m/s²
Explanation:
Given:
v₀ = 0 m/s
v = 11.1 m/s
t = 9 s
Find: a
Equation:
v = at + v₀
Plug in:
11.1 m/s = a (9 s) + 0 m/s
a = 1.23 m/s²
The runner's acceleration is 1.23 m/s².
Answer:
The value of acceleration due to gravity is independent of mass of the body.
Explanation:
Let us consider the mass of the object as m and mass of earth as M
Therefore, force between the object and earth would be given by: F = GMm/d²
This force is equal to the weight of the object, i.e. mg
Thus;
mg = GMm/d²
g = GM/d²
Therefore, the value of acceleration due to gravity is independent of mass of the body.
Answer:
12.5m/s
Explanation:
(Assuming the question was asking for the speed just before it hit the ground)
We can use the first key equation of accelerated motion
Vf^2 = Vi^2+2aΔd
Vf^2 = 0 + 2(9.8)(8) (plugged in values, initial velocity is 0 since the ball was at rest)
Vf^2 = 156.8
Vf = 12.5 (squared both sides)
Answer:
3 Volts
Explanation:
Using Ohm's Law
Voltage=current x resistance
V = I x R
V = 1.5 x 2
V = 3 V
