A rod of length r and mass m is pivoted at its center, and given an angular velocity, ω1. What would be the angular velocity of a second rod, which has the same angular momentum as the first, but whose length is 3r and whose mass is 2m?
1 answer:
Answer:
ω₁ / 18
Explanation:
Angular momentum is the moment of inertia times the angular velocity.
L = Iω
For a rod pivoted at its center, the moment of inertia is:
I = mr² / 12
where m is the mass and r is the length.
For the first rod:
L = (mr² / 12) ω₁
For the second rod:
L = ((2m) (3r)² / 12) ω₂
L = (18mr² / 12) ω₂
They have the same angular momentum, so:
(mr² / 12) ω₁ = (18mr² / 12) ω₂
mr² ω₁ = 18mr² ω₂
ω₁ = 18 ω₂
ω₂ = ω₁ / 18
You might be interested in
Answer:
PLEASE MARK AS BRAINLIEST!!
Explanation:
ANSWER IS IN THE IMG BELOW
Answer:
the answer is a time your welcome
Answer:
can't see anything sorry can't help
The amount of diffraction of sound waves depends on the medium the sound wave travels to and the frequency. Diffraction happens as soon as it has been out of the source.
Sewage. If thats not it, then I need to see your choices. :)