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baherus [9]
3 years ago
10

The minimum stopping distance for a car traveling at a speed of 30 m/s is 60 m, including the distance traveled during the drive

r's reaction time of 0.50 s . What is the minimum stopping distance for the same car traveling at a speed of 50
Physics
1 answer:
makkiz [27]3 years ago
7 0

Answer:

150 m

Explanation:

Distance traveled during reaction time = .5 x 30 = 15 m

Actual distance during which there was deceleration = 60 - 15 = 45 m .

force x displacement = kinetic energy

F x s = 1/2 m v² ;

F x 45 = 1/2 m 30² = 450 m ----( 1 )

for second case

Fx S = 1/2 m 50² = 1250 m --------( 2 )

Dividing( 1 )and ( 2 )

S/45 = 1250 /450 = 125 / 45

S = 125 m

Add distance traveled in reaction time in second case = 50 x .5 = 25 m

total distance required = 25 + 125 = 150 m

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An athlet starting from stationary moves with an acceleration 2.2m/s^2 for 5 seconds, then for other 5 seconds
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Answer:

The graph is shown below.

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Total distance covered is 82.5 m.

Explanation:

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From the graph, the slope of line OA is the acceleration in the first 5 seconds.

Slope of line OA is given as:

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Now, the length AD is nothing but speed at point A or B as AB is a straight line.

Therefore, the speed when crossing the finish line is the speed at B which is equal to 11 m/s.

Distance covered is given by the total area under the graph.

The total area can be divided into two shapes; a triangle and a rectangle.

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Area of triangle OAD is, A_{tri}=\frac{1}{2}\times OD\times AD=\frac{1}{2}\times 5\times 11=27.5

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d_{total}=27.5+55=82.5\textrm{ m}

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Someone please help me answer these
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