For an object that’s in static equilibrium which of the following statements must be true? Check all that apply.

2 answers:

5 0

The statements that are held true with regards to the static equilibrium of bodies are:

The net torque acting on the object must equal zero

The net torque on the object does not have to be zero if the net force on the object is zero

Furthermore, when a body is in a state of static equilibrium, the summation of all forces, either vertically or horizontally, must be equal to zero.

kow [346]3 years ago

5 0

The statements that are held true with regards to the static equilibrium of bodies are:
1. The net torque acting on the object must equal zero.

According to the first Condition of Equilibrium, an object to be in equilibrium, it must have zero acceleration. This means that both the net force and the net torque on the object must be zero and forces acting on it should add up to zero.

2. The net torque on the object does not have to be zero if the net force on the object is zero.

According to the first condition equilibrium, the net force on the object must be zero for the object to be in equilibrium. If net force is zero, the net force along any direction is also zero.

Furthermore, when a body is in a state of static equilibrium, the summation of all forces, either vertically or horizontally, must be equal to zero.

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Answer: 459.14 N

Explanation:

from the question, we have

diameter = 10 m

radius (r) = 5 m

weight (Fw) = 670 N

time (t) = 8 seconds

Circular motion has centripetal force and acceleration pointing perpendicular and inwards of the path, therefore we apply the equation below

∑ F = F c = F w − Fn ..............equation 1

Fn = Fw − Fc = mg − (mv^2 / r) ...................equation 2

substituting the value of v as (2πr / T) we now have

Fn = mg − (m(2πr / T )^2) / r

Fn= mg − (4(π^2)mr / T^2) ..........equation 3

Fw (mass of the person) = mg

therefore m = Fw / g

m = 670 / 9.8 = 68.367 kg

now substituting our values into equation 3

Fn = 670 - ( (4 x (π^2) x 68.367 x 5 ) / 8^2)

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3 years ago

How to find resultant force?

lys-0071 [83]

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Question 2 (10 points)

kenny6666 [7]

The force required to slow the truck was -5020 N

Explanation:

First of all, we find the acceleration of the truck, which is given by

$a=\frac{v-u}{t}$