Answer:
d = 0.71 meters
Explanation:
It is given that,
Charge 1, 
Charge 2, 
Electrostatic force between charges, F = 9 N
Let d is the distance between the charges. The electrostatic force between the charges is given by the product of charges and divided by square of distance between them. Mathematically, it is given by :



d = 0.71 meters
So, the distance between the charges is 0.71 meters. Hence, this is the required solution.
Answer:
a= 17.69 m/s^2
Explanation:
Step one:
given data
A car accelerates uniformly from rest to 23 m/s
u= 0m/s
v= 23m/s
distance= 30m
Step two:
We know that
acceleration= velocity/time
also,
velocity= distance/time
23= 30/t
t= 30/23
t= 1.30 seconds
hence
acceleration= 23/1.30
accelaration= 17.69 m/s^2
Answer:
(177.94 ± 3.81) cm^2
Explanation:
l + Δl = 21.7 ± 0.2 cm
b + Δb = 8.2 ± 0.1 cm
Area, A = l x b = 21.7 x 8.2 = 177.94 cm^2
Now use error propagation



So, the area with the error limits is written as
A + ΔA = (177.94 ± 3.81) cm^2