All categories

2 years ago

What is the are of this triangle? How do you find the area if you don’t know the height to use A=1/2(b) x h

Mathematics

1 answer:

galina1969 [7]2 years ago

3 0

Answer:with that formula you need to change it to be equal to h so you can find it

Step-by-step explanation:

You might be interested in

Use your calculator to evaluate the limit of x equals 1 to 3 of e raised to the x squared power, dx. Give your answer to the nea

xz_007 [3.2K]

The integral of e raised to x squared dx to the limit from 1 to 3 translating in equation we get
∫1-3 e^(X^2) dx.

Solving using scientific calculator, we have 1443.082471 or simply 1443.

ANSWER: 1443

7 0

2 years ago

The following numerically ordered sequence of numbers has a mean of 17 and a median of 18.

Arisa [49]

a= 9

b= 19

hope this helps

8 0

2 years ago

Work out the value of angle x. (24) х Isosceles

andreev551 [17]

answer:

x=78

since it's an isosceles triangle base angles are equal sum of all angles in traingle is 180 so

24+x+x=180

2x=156

x=78

hope.. this helped <3!!!

5 0

2 years ago

The graph of f(x)=ax^2 is narrower than the graph of g(x)=dx^2 when a<d

Lynna [10]

Answer:

Step-by-step explanation:

as given in question that a > 0 so

if we put a=1

we get g(x) = f(x)

now put a =2

we get

g(x) = 2 f(x)

here we can see that g(x) would always be greater than or equals to f(x)

so we can say that the graph of g(x) will never be narrower than graph of g(x)

4 0

2 years ago

fair coin is tossed three times. What is the probability that all three tosses land on heads,given that:(a) the first toss lands

maxonik [38]

Answer:

(a) The probability that all three tosses land on heads given that the 1st toss lands on Heads is $\frac{1}{4}$ .

(b) The probability that all three tosses land on heads given that at least one toss lands on heads is $\frac{1}{7}$ .

Step-by-step explanation:

The sample space of tossing 3 coins is:

S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} = 8 outcomes.

(a)

The sample space such that the 1st toss lands on Heads is:

S₁ = {HHH, HHT, HTH, HTT} = 4 outcomes.

The probability that all three tosses land on heads given that the 1st toss lands on Heads is:

P (3 Heads | 1st toss is Heads) = $\frac{P(3\ Heads\ \cap \ 1st\ toss\ is\ Heads)}{P(1st\ toss\ is\ Heads)}$

$=\frac{\frac{1}{4} }{\frac{4}{8} } \\=\frac{1}{8}\times \frac{8}{4}\\ =\frac{1}{4}$

Thus, the probability that all three tosses land on heads given that the 1st toss lands on Heads is $\frac{1}{4}$ .

(b)

The sample space such that at least one toss lands on heads is:

S₂ = {HHH, HHT, HTH, THH, HTT, THT, TTH} = 7 outcomes

The probability that all three tosses land on heads given that at least one toss lands on heads is,

P (3 Heads | At least 1 Heads) $=\frac{P(3\ Heads\ \cap\ At\ least\ 1\ Heads)}{P( At\ least\ 1\ Heads)}$

$=\frac{\frac{1}{7} }{\frac{7}{8} } \\=\frac{1}{8}\times \frac{8}{7}\\ =\frac{1}{7}$

Thus, the probability that all three tosses land on heads given that at least one toss lands on heads is $\frac{1}{7}$ .

4 0

2 years ago