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SIZIF [17.4K]
2 years ago
8

What volume of 0.140 HCl is needed to neutralize 2.58 of Mg(OH)2 ? ...?

Chemistry
1 answer:
elena-s [515]2 years ago
8 0
To make a first step you have to know the balanced form for neutralization formula: Mg(OH)2(aq)+2HCl(aq)--\ \textgreater \ 2H2O+Mg(aq)+Cl(aq)

According to this, you can <span>calculate what you are being asked :</span>0.0442molMg(OH)2(x)(2molHCl)/(1molMg(OH)2)=0.0885molHCl
Then we have : 0.140MHCl=0.140(mol/L)HCl
Hope everything is clear, here is the exact answer you need : V=(0.0885molHCl)/(0.140(mol/L)HCl)=0.632LHCl&#10;

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Answer:

See explanation below

Explanation:

The question is incomplete. However in picture 1, you have the starting materials and the structure of the product, which you miss in this part.

Now, in picture 2, you have the starting reactant and the product, and the mechanism that is taking place here.

First, all what we have here is an acid  base reaction. In the first step, we are using the acid medium to convert the reactant into an alcohol. The bromine there, is not leaving the molecule yet, because it's neccesary for the next step. The starting reactant is an alkene, in that way, we can convert the reactant in the first step into a secondary alcohol. In other words, the first reaction is a alkene hydration.

In the second step, we use a strong base. You may say this is a strong nucleophile and will do a Sn2 reaction to form another alcohol there, but it's not the case, because, before any kind of reaction happens, the priority here is always the acid base, so the base will react with the acidic hydrogen. In this case, it will substract an hydrogen from the OH. When this happens, the lone pair will do an auto condensation here, and attacks the bromine in the molecule. In this way, the molecule will become a cyclomolecule, and that way it form the final product.

See picture 2, for mechanism

8 0
3 years ago
Which produces the most energy? A. passing 5 kg of water through a hydroelectric power plant. B. fissioning 5 kg of uranium. C.
blagie [28]

Answer:

D. fusing 5 kg of hydrogen.

Explanation:

8 0
2 years ago
Using internet resources, describe the ways radio waves are used on Earth. How do radio telescopes help advance our knowledge of
sammy [17]

Answer: they help advance by being able to see clearly and being able reduce its seeing

Explanation:

3 0
2 years ago
Use the expression we obtained in class to write the molar absorption coefficient of a particular transition in terms of the tra
Anna007 [38]

Answer:

Initially the function is symmetric with respect to the axis of the one dimensional box. In the final state it is also symmetrical, however you can envision a snapshot of the system as the light field is interacting with the wave-function wherein a node begins to develop as is shown in the middle and the wave function is evolving from the initial to final state. Now consider that the electron density during process is the square of the wave function:

Electron density during transition

As can be seen in the initial and final states the electron density is symmetrically distributed with respect to the axis of the box. However with the field on, the electron density is not symmetrically distributed and a transitory dipole moment can be present. To relate back to real molecules think of each of those orbitals as a linear combination of atomic orbitals. One important factor is the symmetry. But there may be one other factor that will be just as important as symmetry. If you treat orbital 1 as a linear combination over n orbitals and orbital 2 as a linear combinations of orbitals as well, there will be a spatial over lap between the orbital in the ground state and the orbital in the excited state. If there is no spatial overlap between the ground state and excited state orbitals there will be no transition dipole moment. However, if the electrons are in the same place spatially, a large transition dipole moment will result.

Explanation:

4 0
2 years ago
You now know that [Pb+2] = 0.17 M. Calculate [Cl-].
iris [78.8K]

Answer:

0.34 M

Explanation:

I assume that the compound is PbCl2.

One mole of PbCl2 contains one mol of Pb+2 and 2 moles of Cl-

Molarity (M)= moles (n) /Volume (V)

Moles Pb2+ = M x V = 0.17 V

Moles Cl- = moles Pb2+ x (2 moles Cl-/1 mole Pb2+) = 0.17 V x 2 = 0.34 V

M Cl- = moles Cl-/V = 0.34V/V = 0.34 M

6 0
2 years ago
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