If the limiting reactant in a chemical reaction is impure, what will happen to the percentage yield of the product?

Which two layers of Earth are mainly composed of metallic elements such as nickel and iron, which are abundant in meteoroids and

Bingel [31]

This layer of the earth lies between the mantle and the solid inner core. It is the only liquid layer, a sea of mostly iron and nickel about 1,400 miles. The lava is mostly made up of iron and nickel. The outer core creates the Earth's magnetic field. The final layer is the inner core, which is 900 miles deep. Scientists believe the inner core is a solid ball of iron and other minerals.

4 0

3 years ago

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The ideal value of the C-0-C angle at atom O2 is degrees.

Tcecarenko [31]

Ethers have a tetrahedral geometry i.e. oxygen is sp
3
hybridized. The C−O−C bond angle is 110
o
. Because of the greater electronegativity of O than C, the C−O bonds are slightly polar & are inclined to each other at an angle of 110
o
, resulting in a net dipole moment. This bond angle greater than that of tetrahedral bond angle of 109
o
28
′
. This is due to the fact that internal repulsion by the hydrocarbon part is greater than the external repulsion of the lone pair of oxygen.

3 0

4 years ago

Why chemically did the prescribing of thalidomide for morning sickness in pregnant women lead to tragic consequences, including

Dominik [7]

Answer:

See explanation

Explanation:

The drug thalidomide with molecular formula C13H10N2O4 was widely prescribed by doctors for morning sickness in pregnant women in the 1960s.

The drug was sold as a racemic mixture (+)(R)-thalidomide and (-)(S)-thalidomide.

Unfortunately, only the (+)(R)-thalidomide exhibited the required effect while (-)(S)-thalidomide is a teratogen.

This goes a long way to underscore the importance of separation of enantiomers in drug production.

Therefore, all the teratogenic effects observed when using the drug thalidomide was actually as a result of the presence of (-)(S)-thalidomide, the unwanted enantiomer.

3 0

3 years ago

A. What are the half-reactions for the redox reaction CuCl2 + Zn → ZnCl2 + Cu? Label the oxidation

GenaCL600 [577]

The oxidation half equation is Zn ------> Zn^2+ + 2e while the reduction half equation is Cu^2+ + 2e------> Cu.

A redox reaction is a reaction in which there is a loss/gain of electrons. The specie that gives out electrons experiences an increase in oxidation number while the specie that gains the electrons experiences a decrease in oxidation number.

For the reaction; CuCl2 + Zn → ZnCl2 + Cu

The oxidation half equation is;

Zn ------> Zn^2+ + 2e

The reduction half equation is;

Cu^2+ + 2e------> Cu

The chloride ion is excluded because its oxidation number does not change from left to right in the reaction.

Learn more: brainly.com/question/967776

3 0

2 years ago

Calculate the Kc for the following reaction if an initial reaction mixture of 0.500 mole of CO and 1.500 mole of H2 in a 5.00 li

Lera25 [3.4K]

Answer:

4.41

Explanation:

Step 1: Write the balanced equation

CO(g) + 3 H₂(g) = CH₄(g) + H₂O(g)

Step 2: Calculate the respective concentrations

$[CO]_i = \frac{0.500mol}{5.00L} = 0.100M$

$[H_2]_i = \frac{1.500mol}{5.00L} = 0.300M$

$[H_2O]_{eq} = \frac{0.198mol}{5.00L} = 0.0396M$

Step 3: Make an ICE chart

CO(g) + 3 H₂(g) = CH₄(g) + H₂O(g)

I 0.100 0.300 0 0

C -x -3x +x +x

E 0.100-x 0.300-3x x x

Step 4: Find the value of x

Since the concentration at equilibrium of water is 0.0396 M, x = 0.0396

Step 5: Find the concentrations at equilibrium

[CO] = 0.100-x = 0.100-0.0396 = 0.060 M

[H₂] = 0.300-3x = 0.300-3(0.0396) = 0.181 M

[CH₄] = x = 0.0396 M

[H₂O] = x = 0.0396 M

Step 6: Calculate the equilibrium constant (Kc)

$Kc = \frac{[CH_4] \times [H_2O] }{[CO] \times [H_2]^{3} } = \frac{0.0396 \times 0.0396 }{0.060 \times 0.181^{3} } = 4.41$

3 0

4 years ago