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3 years ago

15

Which element is least likely to undergo a

1 answer:

aleksley [76]3 years ago

5 0

The element which is least likely to undergo a chemical reaction is (4) neon.
The reason for this is because neon is a noble gas, which means that it doesn't react with other elements as well.

You might be interested in

What happens if an atom loses a neutron?Its mass is lowered, but it is still the same element. Its mass stays the same, and it i

Whitepunk [10]

Answer:

If an atom were to gain or lose neutrons it becomes an isotope. ... If it gains a neutron it become an isotope called deuterium. Since the atomic mass is the total of the number of protons and neutrons, an isotope would have a different atomic mass, but the same atomic number as the original atom

Explanation:

7 0

3 years ago

Read 2 more answers

What is the correct formula of a compound that has ten oxygen atoms and four phosporus atoms?

Arte-miy333 [17]

The correct formula of a compound that has ten oxygen atoms and four phosphorus atoms will be $P_{4} O_{10}$ <u>(tetra phosphorus decoxide)</u>

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Chemical element symbols, numbers, and other symbols, such as parentheses, dashes, brackets, commas, plus as well as minus signs, are used to represent the chemical quantities of the atoms that make up a certain chemical compound and molecule.

It is given that the number of P atom is 4 and 10 oxygen . Decoxide mean

any oxide with ten oxygen molecules per molecule.

Typically, a molecular molecule consists of two or even more nonmetal components. Molecular compounds are characterized by employing the stem of the primary element's term plus the suffix -ide, followed by the second element. The count of atoms in a molecule is specified using numerical prefixes.

Therefore, The correct formula of a compound that has ten oxygen atoms and four phosphorus atoms will be $P_{4} O_{10}$ <u>(</u><u>tetra phosphorus decoxide)</u>

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To know more about compound

brainly.com/question/1563659

#SPJ4

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7 0

1 year ago

Match each type of chemical bond with its properties. Drag the items

natka813 [3]

Explanation:

covalent bond poor thermal conductivity

molecular compounds

metallic bond ductile

electron sea model

ionic bond crystalline

hard and brittle

Covalent compounds have the following properties:

Gases and volatile liquids or low melting point solids
Often insoluble in polar solvents
Mainly non - conductors
Have slow reactions

Metallic compounds:

Have good malleability, ductility, electrical and thermal conductivity.
A large sea of electron by jointly packed atoms.
They are mostly in metals
Accounts for the bulk of the physical properties displayed by metals

Ionic compounds:

High melting and boiling point
Soluble in polar liquids
Conducts electricity in molten or aqueous forms.
Mostly crystalline solids
Usually hard and brittle
Undergoes fast chemical reactions

learn more:

Covalent bonds brainly.com/question/5258547

Ionic bond brainly.com/question/6071838

#learnwithBrainly

5 0

3 years ago

En la reacción I2(g) + Br2(g) « 2 IBr(g), Keq = 280 a 150°C. Suponga que se permite que 0.500 mol de IBr en un matraz de 1.00 L

love history [14]

Answer:

P IBr: 15.454atm

I₂: 0.923 atm

P Br₂: 0.923atm

Explanation:

Basados en la reacción:

I₂(g) + Br₂(g) ⇄ 2 IBr(g)

La constante de equilibrio, Keq, es definida como:

$Keq = \frac{P_{IBr}^2}{P_{I_2}P_{Br_2}}$

<em>Se cumple la relación de Keq = 280 cuando las presiones están en equilibrio</em>

Usando PV = nRT, la presión inicial de IBr es:

P = nRT / V; 0.500mol*0.082atmL/molK*423.15K / 1.00L = <em>17.3 atm</em>

<em />

Siendo las presiones en equilibrio:

P IBr: 17.3 - 2X

P I₂: X

P Br₂: X

<em>Donde X representa el avance de reacción.</em>

Remplazando en Keq:

280 = (17.3 - 2X)² / X²

280X² = 4X² - 69.2X + 299.29

0 = -276X² - 69.2X + 299.29

<em>Resolviendo para X:</em>

X = -1.174 → Solución falsa. No existen presiones negativas

X = 0.923 → Solución real

Así, las presiones parciales en equilibrio de cada compuesto son:

P IBr: 17.3 - 2X = <em>15.454atm</em>

P I₂: X =<em> 0.923atm</em>

P Br₂: X = <em>0.923atm</em>

3 0

3 years ago

Read 2 more answers

Hydrogen gas, iodine vapor, hydrogen iodine are mixed in a flask and heated to 696°C. H2(g) + I2(g) ⇋ 2 HI(g) Kc = 52 at 696°C I

Anettt [7]

Answer: The equilibrium concentration of hydrogen gas is 0.0269 M

Explanation:

The chemical reaction follows the equation:

$H_2(g)+I_2(g)\rightleftharpoons 2HI(g)$

At t = 0 0.044M 0.044M 0.177M

At $t=t_{eq}$ (0.044-x)M (0.044-x)M (0.177+x)M

The expression for $K_c$ for the given reaction follows:

$K_c=\frac{[HI]^2}{[H_2]\times [I_2]}$

We are given:

$K_c=52$

Putting values in above equation, we get:

$52=\frac{(0.177+x)^2}{(0.044-x)^2}$

$x=0.0171M$

Hence, the equilibrium concentration of hydrogen gas is (0.044-x) M =(0.044-0.0171) M= 0.0269 M

7 0

2 years ago