Answer:
-1
Step-by-step explanation:
-100x = 100
-x = 100/100
-x = 1
x = -1
Domain = x<18000(You cant og a negative number)
Am I actually supposed to graph it? enter the equation on desmos.com
It takes longer to make the same altitudinal gain
t=50log(18000/(18000-4000))=50log(18000/14000)=5.457
Answer:
<em>The uniform rate of depreciation is $56,333 per year, or 11% per year.</em>
Step-by-step explanation:
<u>Rate of Depreciation</u>
If some object has a certain value P and after some time t its value decreases to Q, the rate of depreciation is a measure of how much its value changed per unit time.
It can be calculated as:

It can also be expressed as a percentage, dividing the previous value by P.
The school bus reduces its value from $512,000 to $343,000 in 3 years, thus:


R = 56,333 $/year
Expressed as a percentage:
R = 56,333 / 512,000 = 0.11
R = 11%/year
The uniform rate of depreciation is $56,333 per year, or 11% per year.
1 1/16 is it's simplest form.
Answer:
Step-by-step explanation:
Here, 3.2 centimeters on the map is equivalent to 4 kilometers. We can use unitary method to find, how many kilometer/kilometers each centimeter corresponds to. Using the unitary method: Therefore, the scale of map represents 1.25 kilometers for each centimeter.