Answer:
The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy unless it's added from the outside.
Explanation:
Answer:
(i) Al2(SO4)3
(ii) CaCl2
(iii) Fe(OH)2
(iv)AlPO4
(v) Fe(NO3)3
(vi) AuCl3
(vii) AgNO3
Explanation:
The numbers after the element/ion is a subscript meaning its put below the symbol
(i) Al has a charge of 3+ and SO4 has a charge of 2-
So to balance the charges 2 Al is needed to make the charge a 6+ and 3 SO4 is needed to make the charge a 6-. Once you can add the two charge values together to create 0, then you have the correct quantities
(ii) Same applies here, but Ca is 2+ and Cl is 1-, so 2 Cl- is needed to balance out the Ca
(iii) Ferrous is an ion of Iron with a 2+ charge, the other ion of Iron is Ferric which has a 3+ charge. OH has a charge of -1, so 2 OH is needed to balance out one Fe
(iv) Aluminum again has a charge of 3+ while PO4 has a charge of 3-, so they both balance out with one of each.
(v) Ferric is an ion of iron with a charge of 3+ and NO3 has a charge of 1-, so three of NO3 is needed to balance.
(vi) Gold has two charges, 1+ or 3+. However used in Gold chloride it is a 3+ and Cl is a 1-, so 3 of Cl is needed to balance one gold.
(vii) Silver has a charge of 1+ while NO3 has a charge of 1-, so they balance each other at one each.
Answer:
[CICH2COOH] = 0.089 M
[CICH2COO-] = 0.011 M
[H+] = 0.011 M
Ka = 1.36 x 10^-3
Explanation:
The reaction
CICH2COOH ⇄ H+ (aq) + CICH2COO- (aq)
The initial concentration of CICH2COOH is 0.10 M , chloroacetic acid is 11.0% ionized.
let us calculate Ka
First , find change in concentration
since , 11% ionized
change in concentration = 0.10 X 11% = 0.011 M
Initial Concentration of CICH2COOH = 0.10 M
change in concentration of CICH2COOH = - 0.011 M
Equilibrium Concentration of CICH2COOH = 0.10 M - 0.011 M = 0.089 m
Initial Concentration of CICH2COO- = 0 M
change in concentration of CICH2COO- = + 0.011 M
Equilibrium Concentration of CICH2COO- = 0.011 M
Initial Concentration of H+ = 0 M
change in concentration of H+ = + 0.011 M
Equilibrium Concentration of H+ = 0.011 M
Therefore,
[CICH2COOH] = 0.089 M
[CICH2COO-] = 0.011 M
[H+] = 0.011 M
Ka = [H+][CICH2COO-] /[CICH2COOH]
Ka = (0.011 * 0.011) / (0.089)
Ka = 1.36 x 10^-3
Explanation:
I don't understand the question
The results of the experiment that proved atoms contain positive,negative, and neutral particles was that of Rutherford.
<h3>What was Rutherford experiment?</h3>
Rutherford who was a scientist used a gold foil to show that the atom was mainly an empty space. He also discovered that the nucleus was present at the center and there were electrons revolving around it.
This findings led to the proof that atoms contain positive,negative, and neutral particles which is why his experiment was chosen as the most appropriate choice.
Read more about Rutherford experiment here brainly.com/question/14996029
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