Answer:
Explanation:
Answer: The crystal structure of the metal is BCC
Explanation:
we first calculate the volume of the unit cell.
Volume of unit cell= (a°)^3.
The lattice parameter here is a°.
Substitute (6.13 * 10^-8)cm for a°.
Volume of unit cell = (6.13 * 10^-8)^3 = 2.3034 * 10^-22 cm^3/cell.
To determine the crystal structure we use
Density (p) = {(Number of atoms per cell) (Atomic mass)} / {(volume of unit cell)(Avogrado constant)}.
Substitute 1.892g/cm^3 for p (6.02*10^23) atoms/mol for Avogrado constant 1.3921g/mol.
For atomic mass and (2.3034 * 10^-22) cm^3/cell for unit cell.
1.892g/cm^3 = {(Number of atoms per cell) (1.3291g/mol)} / {(2.3034 * 10^-22) (6.02 * 10^23 atoms/mol)}.
Changing the subject of formula we have :
Number of atoms per cell = {(2.3034 * 10^-22) * (6.02 * 10^23) * 1.892} / 132.91
Number of atoms per cell = 2.
Since the number of atoms per cell is 2, :. the crystal structure of metal is BCC.
Note: p = density
a° = a subscript o
