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Olenka [21]
3 years ago
10

Your amplifier is playing a 200 Hz tone. When you double the amplitude(loudness), what happens to the speed of the sound (v) and

the frequency (f)? a. v doubles, f stays the same b. v doubles, f also doubles c. v stays the same, and f doubles d. v and f both stay the same e. v and f both decrease
Chemistry
1 answer:
kherson [118]3 years ago
8 0
Its d. Speed (v) and frequency(f) both stay the same.

<span>Because Amplitude does not affect wave frequency. When you put more energy into the wave (larger amplitude) it does not affect how often you repeat a cycle. 
</span>Also speed can be altered when the medium changes through which it travels.
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At a consent tempture the pressure on a 2.5 l ballon is increased from 2.4 atm to 5.8 atm. what is the new volume?
marissa [1.9K]

Answer:

1.034 L

Explanation:

P1 V1 = P2 V2

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2.4 (2.5) / 5.8 = V2 = 1.034 L

8 0
2 years ago
CHEM! Why do we use roman numerals (aka stock system) when you write the name for a compound with (example:) tin in it even thou
mylen [45]

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7 0
3 years ago
What is the limiting reactant for the following balanced equation when 9 moles of AlF3 are mixed with 12 miles of O2?
tamaranim1 [39]
<h2>Answer:AlF_{3} </h2>

Explanation:

The chemical equation of the reaction that occurs when AlF_{3} reacts with O_{2} is

4AlF_{3}+3O_{2}→2Al_{2}O_{3}+6F_{2}

4 moles of AlF_{3} requires 3 moles of O_{2}.

1 mole of AlF_{3} requires \frac{3}{4} moles of O_{2}.

Given that we have 9 moles of AlF_{3}.

9 moles of AlF_{3} requires \frac{3}{4}\times 9=6.75 moles of O_{2}.

But we have 12 moles of O_{2}.

So,AlF_{3}  will be consumed first.

So,AlF_{3}  is the limiting reagent.

3 0
3 years ago
I need help with this question 20 points and brainiest if ur right
Nutka1998 [239]

Answer:

The volume is 8 cm³

3 0
3 years ago
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Carbohydrates are formed by plants converting water a d carbon dioxide into glucose and oxygen, in the photocatalyzed process is
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