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viva [34]
3 years ago
5

What is the order of magnitude of the gravitational force between two 1.0 kilogram charges that are positioned 1.0 meter apart?

(1) 11 (2) 2 (3) 1 (4) -11
Physics
1 answer:
wariber [46]3 years ago
5 0
I have the sender immediately notify me about this one and only the one you are interested please send us your requirements with you on this site for a few months ago but have not heard back yet over to you as soon and will have to get a new one is the same as last time I have to do it is not an intended solely those are the best way for me to get a good day.
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The spectrum of a distant star shows that one in 2 e6 of the atoms of a particular element is in its first excited state 7.5 eV
Alchen [17]

Answer:

The temperature of star is 5473.87 K

Explanation:

Given:

Energy difference \Delta E = 7.5 eV

The ratio of number of particle \frac{N_{f} }{N_{i} } = \frac{1}{2 \times 10^{6} }

Degeneracy ratio \frac{g_{f} }{g_{i} }  = 4

From the formula of boltzmann distribution for population levels,

     \frac{N_{f} }{N_{i} } =\frac{g_{f} }{g_{i} }  e^{-\frac{\Delta E}{kT} }

Where k = boltzmann constant = 8.62 \times 10^{-5} \frac{eV}{K}

     \frac{1}{2 \times 10^{6} } =4  e^{-\frac{7.5 eV}{8.62 \times 10^{-5} T} }

  8 \times 10^{6} } = e^{\frac{7.5 eV}{8.62 \times 10^{-5} T} }

\ln(8 \times 10^{6})  = {\frac{7.5 eV}{8.62 \times 10^{-5} T} }

  T  = {\frac{7.5 eV}{8.62 \times 10^{-5} \ln(8 \times 10^{6})} }

  T = 5473.87 K

Therefore, the temperature of star is 5473.87 K

5 0
3 years ago
PLEASE ANSWER THIS I AM SO STUCK The increasing trend of energy requirements in the U.S.: a) is directly proportional to populat
stiks02 [169]

Answer:

It should be A

Explanation:

the amount of energy a population has should be based on how many people there are. if more people come into the population, the more energy it should have. if people leave the population, the less energy it should have.

7 0
3 years ago
What do all waves, including sound and light, have in common​
Schach [20]

Answer:

They all have frequency, wavelength, amplitude, speed and also all transfer energy.

6 0
3 years ago
Please Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
arsen [322]

Answer:

Given that

speed u=4*10^6 m/s

electric field E=4*10^3 N/c

distance b/w the plates d=2 cm

basing on the concept of the electrostatices

now we find the acceleration b/w the plates  to find the horizontal distance traveled by the electron when it hits the plate.

acceleration a=qE/m=1.6*10^{-19}*4*10^3/9.1*10^{-31} =0.7*10^{15}=7*10^{14} m/s

now we find the horizontal distance traveled by electrons hit the plates

horizontal distance

X=u[2y/a]^{1/2}

=4*10^6[2*2*10^{-2}/7*10^{14}]^{1/2}

=3*10^{-2}= 3 cm

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3 years ago
The cardiovascular system consists of
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Consists of A. good luck
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