Complete question:
A 200 g load attached to a horizontal spring moves in simple harmonic motion with a period of 0.410 s. The total mechanical energy of the spring–load system is 2.00 J. Find
(a) the force constant of the spring and (b) the amplitude of the motion.
Answer:
(a) the force constant of the spring = 47 N/m
(b) the amplitude of the motion = 0.292 m
Explanation:
Given;
mass of the spring, m = 200g = 0.2 kg
period of oscillation, T = 0.410 s
total mechanical energy of the spring, E = 2 J
The angular speed is calculated as follows;

(a) the force constant of the spring

(b) the amplitude of the motion
E = ¹/₂kA²
2E = kA²
A² = 2E/k

Normally, the number of electrons is equal to the number of protons, which makes atoms electrically neutral. The number of protons in an atom is the defining feature of an atom. It's what makes one element different from another
HOPE THIS HELPS!!!
Answer:
Third → First → Second → Fourth
Explanation:
Initially helium and Hydrogen in abundance started to form atoms
Following the atoms formation by hydrogen and helium bombardment of new matter into the Earth took place.
The bombardment of matter resulted in separation of Earth into respective layers based on the weight of the matter.
A primitive ocean was created as a result of off gassing of the volcanoes.