Explanation:
The formula we are going to use is
Pressure = F/A
Elephant:
First, we need to convert weight into newtons.
1kg=9.8 newtons, so 2800kg × newtons = 27440newtons
For 4 feet= 200×4= 800cm^2
Convert the area to meter squared using the following:
1 centimeter squared = 0.0001 meters squared
800cm^2×0.0001= 0.08m^2
Pressure=F/A
Pressure= 27440/0.08
The pressure exerted on the ground by the elephant is 343000 Pascals.
Vulture:
12kg×9.8=117.6newtons
for 2 feet= 2.0×2=4cm^2
4×0.0001=0.0004m^2
117.6/0.0004= 294000 Pascals
To compare the pressure, just do a ratio of the elephant's pressure to vulture's pressure.
343000/294000≈ 1.17
So the pressure is about 1 times bigger.
Keep in mind that the elephant has 4 feet, which help to increase the area which in turn decrease the pressure.
I got a different answer for #2
The minimum coefficient of friction to avoid slippage of the coin is 0.23.
<h3>
Minimum coefficient of friction</h3>
The minimum coefficient of friction can determined from the maximum speed of the coin.
ma = μmg
mv²/r = μmg
v²/r = μg
v² = μgr
μ = v²/(gr)
μ = (ωr)²/(gr)
μ = ω²r/g
μ = (7.95² x 0.035)/(9.8)
μ = 0.23
Learn more about coefficient of friction here: brainly.com/question/20241845
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