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den301095 [7]
3 years ago
9

Which of the following describes water's ability to dissolve substances?

Chemistry
1 answer:
kicyunya [14]3 years ago
7 0
Water is polar and dissolves polar substances
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If 100 g of a substance reacts with 70 g of another substance, what will be the mass of the products after the reaction?
RideAnS [48]

Answer:

x=170

The question is asking you to add them together to get your unknown number

7 0
3 years ago
How does atomic mass differ from atomic number
Lina20 [59]
The atomic mass is the average mass of all the isotopes. The atomic number is the number of protons in the nucleus of an atom. In an uncharged atom the atomic number is also equal to the number of electrons. 

Hope this helps!
3 0
4 years ago
Read 2 more answers
A 23.5g aluminum block is warmed to 65.9°C and plunged into an insulated beaker containing 55.0g water initially at 22.3°C. The
atroni [7]

Answer:

25.97oC

Explanation:

Heat lost by aluminum = heat gained by water

M(Al) x C(Al) x [ Temp(Al) – Temp(Al+H2O) ] = M(H2O) x C(H2O) x [ Temp(Al+H2O) – Temp(H2O) ]

Where M(Al) = 23.5g, C(Al) = specific heat capacity of aluminum = 0.900J/goC, Temp(Al) = 65.9oC, Temp(Al+H2O)= temperature of water and aluminum at equilibrium = ?, M(H2O) = 55.0g, C(H2O)= specific heat capacity of liquid water = 4.186J/goC

Let Temp(Al+H2O) = X

23.5 x 0.900 x (65.9-X) = 55.0 x 4.186 x (X-22.3)

21.15(65.9-X) = 230.23(X-22.3)

1393.785 - 21.15X = 230.23X – 5134.129

230.23X + 21.15X = 1393.785 + 5134.129

251.38X = 6527.909

X = 6527.909/251.38

X = 25.97oC

So, the final temperature of the water and aluminum is = 25.97oC

4 0
3 years ago
A prototype is usually different from the final product
Assoli18 [71]
True. The prototype is usually the "rough draft" the figure out what needs fixed or upgraded before they make the final product "final draft". Hope that helped!
7 0
3 years ago
Calculate the volume of liquid in the tank sketched below. Give your answer in liters, and round to the nearest 0.1 L.
wariber [46]

Answer:

1.3 L

Explanation:

The volume of a rectangular cube can be calculated using the following formula:

Volume (L) = length (cm) x width (cm) x height (cm)

Keep in mind that 1 L = 1,000 cm³.

Before you can plug the values into the equation, you need to make sure they all have the same unit. Since the length is in meters (m), you need to first convert it to centimeters.

1 meter = 100 cm

 0.159 m           100 cm
---------------  x  ----------------  =  15.9 cm
                           1 m

Now, you can solve for the volume. To find the answer is the unit liters, you need to divide the volume by 1,000.

Volume = l x w x h

Volume = 15.9 cm x 10.5 cm x 7.7 cm

Volume = 1,285.5 cm³

Volume = 1.2855 L ------>  Volume = 1.3 L

7 0
2 years ago
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