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zhenek [66]
2 years ago
6

arrange these species by their ability to act as an oxidizing agent.you are currently in a ranking module. turn off browse mode

or quick nav, tab to move, space or enter to pick up, tab to move items between bins, arrow keys to change the order of items, space or enter to drop.best oxidizing agentpoorest oxidizing agent
Chemistry
1 answer:
morpeh [17]2 years ago
5 0

The arrangement of the species from best oxidizing agent to poorest oxidizing agent is:

  • Ag⁺
  • Ni²⁺
  • Fe²⁺
  • Al³⁺

<h3>What are oxidizing agents?</h3>

Oxidizing agents are agents which oxidizes other species but are themselves reduced.

Oxidizing agents accept electrons from electron donors.

Non-metals are good oxidizing agents.

The oxidization potential of metals increases with increasing positive values of reduction potential.

In conclusion, oxidizing agents accept electrons are themselves reduced.

Learn more about oxidizing agents at: brainly.com/question/1390694

#SPJ1

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The gas in a cylinder has a volume of 7 liters at a pressure of 107kPa. The pressure of the gas is increased to 208kPa. Assuming
VashaNatasha [74]
By Boyles Law (P1V1=P2V2), substituting values in and solving for V2, we find that the new volume is 3.6 L<span />
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3 years ago
What is oxidation number of S in H2SO5??​
mote1985 [20]

★ « <em><u>what is oxidation number of S in H2SO5??</u></em><em><u> </u></em><em><u>»</u></em><em><u> </u></em><em><u>★</u></em>

  • <em><u>it's </u></em><em><u> </u></em><em><u>6</u></em><em><u>!</u></em><em><u>!</u></em>

Explanation:

  • <em>Oxidation number of S in H2SO5 is 6 .</em>
3 0
3 years ago
Read 2 more answers
What is the correct name of the compound Mn3(PO4)2? A. manganese phosphate B. manganese(I) phosphate C. manganese(III) phosphate
Sergio039 [100]
The correct name of the compound Mn3(PO4)2 is  definitely the last option represented above <span>D. manganese(II) phosphate. I am pretty sure this answer will help you

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3 0
3 years ago
Prform the following operation and express the answer in scientific notation 6.0 x 10^3-2.310^3
Marrrta [24]

The value 6.0 x 10^3- 2.3 × 10^3 in scientific notation is 3.7 × 10^3.

<h3> What is scientific notation?</h3>

Scientific notation is a way to write very large or very small numbers so that they are easier to read and work with.

You express a number as the product of a number greater than or equal to 1 but less than 10 and an integral power of 10 .

<h3>Why it is used? </h3>

There are two reasons to use scientific notation.

  • The first is to reveal honest uncertainty in experimental measurements.
  • The second is to express very large or very small numbers so they are easier to read.

Given,

= 6.0 x 10^3- 2.3 × 10^3

= (6.0 - 2.3) × 10^3

= 3.7 × 10^3

Thus, we find that the value 6.0 x 10^3- 2.3 × 10^3 in scientific notation is 3.7 × 10^3.

learn more about scientific notation :

brainly.com/question/18073768

#SPJ1

3 0
2 years ago
Determine the molarity of a 6.0 mole% sulfuric acid solution with SG-a 1.07 Note: Atomic Weight: S (32), O 16); H (O)
marin [14]

Answer:

The molarity of a 6.0 mole% sulfuric acid solution is 2.8157 Molar.

Explanation:

Suppose there are 100 moles in solution:

Moles of sulfuric acid = 6% of 100 moles = 6 moles

Mass of 6 moles of sulfuric acid = 6 mol × 98 g/mol=588 g

Moles of water = 100%- 6% = 94%= 94 moles

Mass of water = 94 mol × 18 g/mol = 1692 g

Specific gravity of the solution ,S.G= 1.07

Density of solution = D

S.G=\frac{D}{d_w}

d_w = density of water = 1 g/mL

D=S.G\times d_w=1.07\times 1 g/mL=1.07 g/mL

Mass of the solution = 588 g + 1692 g = 2280 g

Volume of the solution = V

Volume = \frac{Mass}{Density}

=\frac{2280 g}{1.07 g/mL}=2130.84 mL=2.13084 L

1 mL = 0.001 L

Molarity = \frac{n}{V(L)}

n = number of moles of compound

V = volume of the solution in L

here we have ,n = 6 moles of sulfuric acid

V = 2.13084 L

So, the molarity of the solution is :

Molarity=\frac{6 mol}{2.13084 L}=2.8157 mol/L

5 0
3 years ago
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