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Sav [38]
3 years ago
9

What piece of apparatus is the ink mixture put in

Chemistry
1 answer:
erik [133]3 years ago
3 0

Answer:

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Is there a way to dissolve more sugar into a solution that it should hold at that temperature? Explain how this is done and what
Darya [45]

The answer is: supersaturated solution.

A supersaturated solution contains more of the dissolved substance than could be dissolved by the solvent under normal circumstances.

A way to dissolve more sugar into a solution is heating a solution.

The more heat is added to a system, the more soluble a substance (in this example sugar) becomes.

The solution will become supersaturated if this solution is suddenly cooled at a rate faster than the rate of precipitation.

6 0
3 years ago
(07.06 mc)
Slav-nsk [51]

Distilled water and sealed container are in equilibrium when these objects do not exchange more heat.

<h3>What is thermal equilibrium?</h3>

The expression 'thermal equilibrium' makes references to the phenomenon by which two objects interact with each other to exchange heat energy.

Objects in contact can transfer heat to reach a thermal equilibrium state where the temperature is the same for both objects.

In conclusion, distilled water and sealed container are in equilibrium when these objects do not exchange more heat.

Learn more on thermal equilibrium here:

brainly.com/question/9459470

#SPJ1

5 0
2 years ago
Calculate the pH after 10 mL of 1.0 M sodium hydroxide is added to 60 mL of 0.5M acetic acid.
baherus [9]

Explanation:

It is given that the total volume is (10 mL + 60 mL) = 70 mL.

Also, it is known that M_{1}V_{1} = M_{2}V_{2}

Where,    V_{1} = total volume

               V_{2} = initial volume

Therefore, new concentration of CH_{3}COOH = \frac{M_{2}V_{2}}{V_{1}}

                                        = \frac{60 \times 0.5}{70}

                                        = 0.43 M

New concentration of NaOH = \frac{M_{2}V_{2}}{V_{1}}

                                               = \frac{10 \times 1.0}{70}

                                               = 0.14 M

So, the given reaction will be as follows.

              CH_{3}COOH + OH^{-} \rightarrow CH_{3}COO^{-} + H_{2}O

Initial:             0.43          0.14                     0

Change:          -0.14        -0.14                    0.14

Equilibrium:    0.29          0                       0.14

As it is known that value of pK_{a} = 4.74

Therefore, according to Henderson-Hasselbalch equation calculate the pH as follows.

           pH = pK_{a} + log \frac{[CH_{3}COO^{-}]}{[CH_{3}COOH]}

                 = 4.74 + log \frac{0.14}{0.29}

                 = 4.74 + (-0.316)

                 = 4.42

Therefore, we can conclude that the pH of given reaction is 4.42.

6 0
3 years ago
Check my work please
a_sh-v [17]

Answer:

ur correct. except for type of reaction is Exothermic

Explanation:

im a teacher!

3 0
4 years ago
How many moles of N₂ are essential for generating 0.08 moles of Li₃N in the given reaction?
joja [24]
Each mole of N₂ generates 2 moles of Li₃N. Thus,
0.08 moles of Li₃N will require:
0.08 / 2
= 0.04 moles of N₂

The second option is correct.
4 0
3 years ago
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