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professor190 [17]
3 years ago
8

According to Newton’s Law of gravity, which of the following is inversely related to the square of the distance from earth?

Physics
2 answers:
Dima020 [189]3 years ago
3 0
I think it’s D

I hope this helps ❤️
Travka [436]3 years ago
3 0

Answer:

B. Weight

Explanation:

If you look at my crude drawing of two bodies attracted by each other (hey that's gravity, not love!) and to Newton's law of gravity:

F_{1} =F_{2} =G\frac{m_{1} m_{2} }{r^{2} }

For this to work we have to assume that the Forces are equal and the whole system is in equilibrium.

Now if we take a look at the picture, r is the distance between the two bodies, G is the gravitational constant, and m is the mass either of body 1 or 2, so, if we increase the distance, the force of gravity will decrease by the square root of that unit, because it is the denominator of the fraction.

Now emphasis on "Force of Gravity" Force is the only factor inversely proportionate to the square root of the distance, and the only answer that is actually a Force from the options is weight (m*g).

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Force needed is 5×6=30
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How long does it take light from a camera to travel to the face of someone standing 7 meters away?
mestny [16]

The time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

Speed is simply defined as the distance travelled per unit time. Mathematically, it is expressed as:

<h3>Speed = distance / time </h3>

With the above formula, we can obtain the time taken for the light to travel from the camera to someone standing 7 m away. This can be obtained as follow:

Distance = 7 m

Speed of light = 3×10⁸ m/s

<h3>Time =?</h3>

Time = Distance / speed

Time = 7 / 3×10⁸

<h3>Time = 2.33×10¯⁸ s</h3>

Therefore, the time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

Learn more: brainly.com/question/14988345

8 0
2 years ago
A mobile starts with a speed of 250m / s and begins to decelerate at a rate of 3m / s². How fast is it after 45s?
Korvikt [17]

\large{ \underline{ \underline{ \bf{ \purple{Given}}}}}

  • Speed of the mobile = 250 m/s
  • It starts decelerating at a rate of 3 m/s²
  • Time travelled = 45s

\large{ \underline{ \underline{ \bf{ \green{To \: find}}}}}

  • Velocity of mobile after 45 seconds

\large{ \underline{ \underline{ \red{ \bf{Now, \: What \: to \: do?}}}}}

We can solve the above question using the three equations of motion which are:-

  • v = u + at
  • s = ut + 1/2 at²
  • v² = u² + 2as

So, Here a is acceleration of the body, u is the initial velocity, v is the final velocity, t is the time taken and s is the displacement of the body.

\large{ \bf{ \underline{ \underline{ \orange{Solution:}}}}}

We are provided with,

  • u = 250 m/s
  • a = -3 m/s²
  • t = 45 s

By using 1st equation of motion,

⇛ v = u + at

⇛ v = 250 + (-3)45

⇛ v = 250 - 135 m/s

⇛ v = 115 m/s

✤ <u>Final</u><u> </u><u>velocity</u><u> </u><u>of</u><u> </u><u>mobile</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u>5</u><u> </u><u>m</u><u>/</u><u>s</u>

<u>━━━━━━━━━━━━━━━━━━━━</u>

4 0
3 years ago
Suppose a sound wave and an electromagnetic wave have the same frequency. Which has the longer wavelength? 1. the electromagneti
Mashcka [7]

Answer:

1. the electromagnetic wave.

Explanation:

Mathematically,

wavelength = velocity ÷ frequency

A mechanical wave is a wave that is not capable of transmitting its energy through a vacuum. Mechanical waves require a medium in order to transport their energy from one location to another. A sound wave is an example of a mechanical wave. Sound waves are incapable of traveling through a vacuum.

Electromagnetic waves of different frequency are called by different names since they have different sources and effects on matter, increasing frequency decreases wavelength.

Sound waves (which obviously travel at the speed of sound) are much slower than electromagnetic waves (which travel at the speed of light.)  

Electromagnetic waves are much faster than sound waves and If the Velocity of the wave increases and the frequency is constant, the wavelength also increases.

7 0
4 years ago
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