The energy changes involved when a positive charge moves because of a nearby, negatively charged object because that is actually similar to when an object falls in a gravitational field, the potential energy of the object will turn in to a kinetic energy. thank you for this question.
Answer:
( 1000 × 4 = 4,000) (800×3= 2400) (800×2=1600) the answer is 1600 hope it helps
Answer:
Having a bigger angle above the horizontal
Explanation:
Applying the energy conservation theorem:
The kinetic energy is reduced because of the work done by the friction force.
The friction force is given by:
so the friction force depends on the Normal force, because the slide has an angle the normal force is given by:
So when the angle of the slide is bigger, the friction force decreases, for example:
for 45 degrees:
for 75 degrees:
as you can see if the angle is bigger above the horizontal, the friction force is reduced and so the work done by that force. We didn't have to change the height of the slide, so the potential gravitational energy remains the same.
Answer:
The final kinetic energy of the Helium nucleus (alpha particle) after been scattered through an angle of 120° is
8.00 x 10-13J
Explanation:
In Rutherford Scattering experiment, the collision of the helium nucleus with the gold nucleus is an ELASTIC COLLISION. This means that the kinetic energy is conserved ( The same before and after the collision).
Thus, the final kinetic energy of the helium nucleus is the same as initial kinetic energy (8.00 x 10^-13Joules)
Although, the kinetic energy is converted to potential energy in Coulomb's law equation.
That is,
1/2(mv^2) = (K* q1q2)/r
Where m is the mass of helium nucleus, v is its colliding velocity, k is electrostatic constant, q1 is the charge on helium nucleus, q2 is the charge on gold nucleus, r is impact parameter
