Answer:
The correct answer is option C.
Explanation:
A. The -COOH group would experience hydrogen bonding with water.
The statement is true because , double bonded oxygen atom of carboxylic group interacts with hydrogen atom of water molecule and oxygen atom of water molecule is in same interaction with hydrogen atom of carboxylic acid.
B. The long alkane ''tail" 
, is hydrophobic.
The statement is true because , region which do not interacts with water molecule is termed as hydrophobic region and region which do interacts with water molecule is termed as hydrophilic region. Generally ,alkanes are are hydrophobic in nature so is the alkane chain in stearic acid.
C. Stearic acid and water are probably miscible.
The statement is false because of higher hydrophobic region the interaction between the acid molecules and water molecules results in immiscibility.
D. Stearic acid would probably dissolve in non polar solvents such as hexane 
.
The statement is true because of hydrophobic part in stearic acid is larger so that is why it get easily dissolve in non polar solvents.
E. Stearic acid contains hydrophobic regions
The statement is true because of higher hydrophobic region due to which they easily get dissolved in organic and non polar solvents.
35.9 g of PCl₅ will be required to produce produce 12.6 g of HCl.
<h3>Equation of the reaction</h3>
The equation of the reaction is given below:
PCl₅ + H2O ---> POCl₃ + 2 HCl
<h3>How to calculate grams of PCl₅ required to produce 12.6 g of HCl</h3>
Molar mass of PCl₅ = 208.5 g
Molar mass of Hcl = 36.5 g
Moles of HCl = mass / molar mass
Moles of HCl = 12.6 / 36.5
moles of HCl = 0.345 moles
2 moles of HCl are produced by 1 mole of PCl₅
0.345 moles of HCl will be produced by 0.345/2 = 0.1725 moles of PCl₅
Mass of 0.1725 moles of PCl₅ = 0.1725 * 208.5 = 35.9 g of PCl₅
Mass of PCl₅ = 35.9 g of PCl₅
Therefore, 35.9 g of PCl₅ will be required to produce produce 12.6 g of HCl.
Learn more about mass and molar mass at: brainly.com/question/15476873
Answer:
1. start line drawn in ink
2. start line below solvent level
Explanation:
1. the line would run up the paper. should have drawn with pencil.
2. the samples would dissolve into solvent and not run up the paper.
Answer:
B) hydroxide concentration
Explanation:
Hello,
In this case, since we are talking about strong both base and acid, since the base is the titrant and the acid the analyte, once the equivalence point has been reached, some additional base could be added before the experimenter realizes about it, therefore, since the titrant is a strong base, it completely dissociates in hydroxide ions and metallic ions which allows us to compute the pOH of the solution by known the hydroxide ions concentration.
After that, due to the fact that the pH is related with the pOH as shown below:
pH=14-pOH
We can directly compute the pH.
Best regards.
