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Fofino [41]
3 years ago
10

What is the molar mass of calcium chloride dihydrate (CaCl2 • 2H2O)? Be sure to

Chemistry
1 answer:
Verdich [7]3 years ago
4 0

Calcium chloride dehydrate (CaCl₂ · 2 H₂O) have a molar mass equal to 147 g/mol.

Explanation:

To calculate the molar mass of calcium chloride dehydrate (CaCl₂ · 2 H₂O) we use the following formula:

molar mass of CaCl₂ · 2 H₂O = atomic weight of Ca × 1 + atomic weight of Cl × 2 + atomic weight of H × 4 + atomic weight of O × 2

molar mass of CaCl₂ · 2 H₂O = 40 × 1 + 35.5 × 2 + 1 × 4 + 16 × 2

molar mass of CaCl₂ · 2 H₂O = 147 g/mol

Learn more about:

molar mass

brainly.com/question/6112557

#learnwithBrainly

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Stearic acid, fatty acid commonly found in animal fat has a condensed Chemical formula CH3(CH2)16COOH. It is a common component
timofeeve [1]

Answer:

The correct answer is option C.

Explanation:

A. The -COOH group would experience hydrogen bonding with water.

The statement is true because , double bonded oxygen atom of carboxylic group interacts with hydrogen atom of water molecule and oxygen atom of water molecule is in same interaction with hydrogen atom of carboxylic acid.

B. The long alkane ''tail" CH_3(CH_2)_{16} -, is hydrophobic.

The statement is true because , region which do not interacts with water molecule is termed as hydrophobic region and region which do interacts with water molecule is termed as hydrophilic region. Generally ,alkanes are are hydrophobic in nature so is the alkane chain in stearic acid.

C. Stearic acid and water are probably miscible.

The statement is false because of higher hydrophobic region the interaction between the acid molecules and water molecules results in immiscibility.

D. Stearic acid would probably dissolve in non polar solvents such as hexane C_6H_{14}.

The statement is true because of hydrophobic part in stearic acid is larger so that is why it get easily dissolve in non polar solvents.

E. Stearic acid contains hydrophobic regions

The statement is true because of higher hydrophobic region due to which they easily get dissolved in organic and non polar solvents.

6 0
3 years ago
3. If you want to produce 12.6 g of HCl, how many grams of PCls will you need?
Ratling [72]

35.9 g of PCl₅ will be required to produce produce 12.6 g of HCl.

<h3>Equation of the reaction</h3>

The equation of the reaction is given below:

PCl₅ + H2O ---> POCl₃ + 2 HCl

<h3>How to calculate grams of PCl₅  required to produce 12.6 g of HCl</h3>

Molar mass of PCl₅ = 208.5 g

Molar mass of Hcl = 36.5 g

Moles of HCl = mass / molar mass

Moles of HCl = 12.6 / 36.5

moles of HCl = 0.345 moles

2 moles of HCl are produced by 1 mole of PCl₅

0.345 moles of HCl will be produced by 0.345/2 = 0.1725 moles of PCl₅

Mass of 0.1725 moles of PCl₅ = 0.1725 * 208.5 = 35.9 g of PCl₅

Mass of PCl₅ = 35.9 g of PCl₅

Therefore, 35.9 g of PCl₅ will be required to produce produce 12.6 g of HCl.

Learn more about mass and molar mass at: brainly.com/question/15476873

4 0
2 years ago
Please help due tomorrow science
horrorfan [7]

Answer:

1. start line drawn in ink

2. start line below solvent level

Explanation:

1. the line would run up the paper. should have drawn with pencil.

2. the samples would dissolve into solvent and not run up the paper.

8 0
3 years ago
When titrating a strong acid with a strong base, after the equivalence point is reached, the pH will be determined exclusively b
Arte-miy333 [17]

Answer:

B) hydroxide concentration

Explanation:

Hello,

In this case, since we are talking about strong both base and acid, since the base is the titrant and the acid the analyte, once the equivalence point has been reached, some additional base could be added before the experimenter realizes about it, therefore, since the titrant is a strong base, it completely dissociates in hydroxide ions and metallic ions which allows us to compute the pOH of the solution by known the hydroxide ions concentration.

After that, due to the fact that the pH is related with the pOH as shown below:

pH=14-pOH

We can directly compute the pH.

Best regards.

5 0
3 years ago
Please I need help with all the questions 1-5 and inn struggling with it and if you need to see the picture big then click on it
irakobra [83]
It’s hard to zoom in and read the questions
8 0
4 years ago
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