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mote1985 [20]
3 years ago
7

The formation of lithium fluoride (seen here) is due to A) a stronger pull by the lithium atom on its valence electron. B) incre

ased stability in the completion of fluorine's outer shell. C) the addition of an outer (higher) energy level in the fluoride ion. D) decreased attraction between the lithium and fluoride ions.
Chemistry
2 answers:
Nastasia [14]3 years ago
4 0

Answer:

B.

Explanation:

Increased stability in fluoride ion.

Troyanec [42]3 years ago
4 0

Answer:

The correct answer is option B) greater stability in the termination of the outer fluorine layer

Explanation:

Hello! Let's solve this!

In the formation of lithium fluoride, lithium gives up its electron to stabilize the last layer of the fluorine, which in turn accepts that electron.

The compound is a neutral salt.

The correct answer is option B) greater stability in the termination of the outer fluorine layer.

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Answer:

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Explanation:

First of all we will write the balance chemical equation.

2AgNO₃ + Na₂CrO₄     →    Ag₂CrO₄  +  2NaNO₃

Now we will calculate the moles of AgNO₃.

Number of moles = mass / molar mass

Molar mass of AgNO₃ = 107.87 + 14 + 3× 16 =  169.87 g/mol

Number of moles = mass / molar mass

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Now we will compare the moles of AgNO₃ and  Na₂CrO₄ from balance chemical equation.

                        AgNO₃    :     Na₂CrO₄

                          2            :           1

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Now we will calculate the mass of Na₂CrO₄.

Molar mass of Na₂CrO₄ = 23×2 + 52 + 16×4 = 162 g/mol

Mass of Na₂CrO₄ = number of moles  ×  molar mass

Mass of Na₂CrO₄ =  0.0355 mol ×  162 g/mol

Mass of Na₂CrO₄ =  5.75 g

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3 years ago
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Answer:

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Explanation:

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2 years ago
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