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mote1985 [20]
2 years ago
7

The formation of lithium fluoride (seen here) is due to A) a stronger pull by the lithium atom on its valence electron. B) incre

ased stability in the completion of fluorine's outer shell. C) the addition of an outer (higher) energy level in the fluoride ion. D) decreased attraction between the lithium and fluoride ions.
Chemistry
2 answers:
Nastasia [14]2 years ago
4 0

Answer:

B.

Explanation:

Increased stability in fluoride ion.

Troyanec [42]2 years ago
4 0

Answer:

The correct answer is option B) greater stability in the termination of the outer fluorine layer

Explanation:

Hello! Let's solve this!

In the formation of lithium fluoride, lithium gives up its electron to stabilize the last layer of the fluorine, which in turn accepts that electron.

The compound is a neutral salt.

The correct answer is option B) greater stability in the termination of the outer fluorine layer.

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What is easier to observe about an object,it’s physical properties or it’s chemical properties. Explain why.
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Explanation:

You are able to see physical properties but are unable to see chemical properties.

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What are the three types of protist and how are they similar and how are they different (this is science but there is no tab for
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How many mole of H2 will be produced if 0.500 grams of magnesium is reacted with 10.00mL of 2.0 M HCl?
Ratling [72]
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7 0
3 years ago
Which of the following is a product of aerobic respiration?
sasho [114]

Answer:

The product of aerobic respiration is Carbon dioxide.

Explanation:

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3 0
3 years ago
Read 2 more answers
The oxidation of Cu₂O(s) to CuO(s) is an exothermic process:
Alex73 [517]

Answer:

w = 7376.6 J

Explanation:

To calculate the work done in the system, we need first to calculate the number of moles of all compounds.

The following expression, that comes from the 1° law of thermodynamic, will help you to get the work:

w = ΔnRT

Where:

Δn: difference in the number of moles between products and reactants

R: constant universal of gases (8.314 J / mol K)

T: Temperature in Kelvin.

As we are doing this reaction in STP, then the Pressure is 1 atm, and temperature is 0 °C or 273 K.

Now, we already have the moles of Cu₂O, let's see, according to the balanced reaction, how many moles we should have of O₂ and CuO.

If 1 mole of O₂ reacts with 2 moles of Cu₂O then 6.5 moles of Cu₂O will be:

moles O₂ = 6.5 moles Cu₂O * (1 mole O₂/2 moles Cu₂O) = 3.25 moles O₂

If 2 moles of Cu₂O produces 4 moles of CuO, then 6.5 moles will be:

moles CuO = 6.5 moles Cu₂O*(4 moles CuO/2 moles Cu₂O) = 13 moles CuO

Now that we have the moles, let's calculate the value of Δn.

Δn = moles product - moles reactants

Δn = 13 - (6.5 + 3.25) = 3.25 moles

Now, we can calculate the work done in the system:

w = 3.25 * (8.314 * 273)

<h2>w = 7376.6 J or 7.3766 kJ</h2>

Hope this helps

8 0
2 years ago
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