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mote1985 [20]
3 years ago
7

The formation of lithium fluoride (seen here) is due to A) a stronger pull by the lithium atom on its valence electron. B) incre

ased stability in the completion of fluorine's outer shell. C) the addition of an outer (higher) energy level in the fluoride ion. D) decreased attraction between the lithium and fluoride ions.
Chemistry
2 answers:
Nastasia [14]3 years ago
4 0

Answer:

B.

Explanation:

Increased stability in fluoride ion.

Troyanec [42]3 years ago
4 0

Answer:

The correct answer is option B) greater stability in the termination of the outer fluorine layer

Explanation:

Hello! Let's solve this!

In the formation of lithium fluoride, lithium gives up its electron to stabilize the last layer of the fluorine, which in turn accepts that electron.

The compound is a neutral salt.

The correct answer is option B) greater stability in the termination of the outer fluorine layer.

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On the first day of your new job as a chemist, you are given a bottle of magnesium sulfate and asked to make 30 mL of 0.3 M MgSO
Lady bird [3.3K]

Answer:

The answer to your question is 15500 mg of MgSO₄ 7H₂O

Explanation:

Data

Volume = 30 ml

Concentration = 0.3 M

Formula MgSO4∗7H2O

Process

1.- Calculate the number of moles needed

 Molarity = moles / volume

Solve for moles

 moles = Molarity x volume

Substitution

 moles = 0.3 x 0.03 l

 moles = 0.009 moles of MgSO₄

2.- Calculate the molecular mass of MgSO4∗7H2O

molecular mass = 24 + 32 + 64 + 14 + 112

                           = 246 g

3.- Get the proportion MgSO4 :7H2O, this proportion is 1 : 7

4.- Calculate the amount of MgSO4∗7H2O

    0.009 mol of MgSO4 \frac{7 MgSO4 7H2O}{1 mol MgSO4} \frac{246 g MgSO4 7H2O}{1 mol MgSO4 7H2O}

Simplification

   15.5 g = 15500 mg

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