The oxidation state of an element is an indicator of the total number of electrons that have been removed from the atom. The oxidation state of a)HIO₂ is +3, meaning that three electrons have been removed from the atom.
The oxidation state of an atom is determined by the oxidation number of its constituent elements. In the case of HIO₂, the oxidation number of each atom is determined by the sum of the number of valence electrons and the charge of the ion. The oxidation number of hydrogen is +1, the oxidation number of oxygen is -2 and the oxidation number of iodine is +7. When these values are added together, the oxidation number of HIO₂ is +3.
Oxidation states can be useful in predicting the stability of a compound and the reactivity of the atoms within it. In this case, the oxidation state of HIO₂ indicates that it is relatively stable, as the total oxidation number for the molecule is positive. The positive oxidation state also indicates that HIO₂ is likely to be fairly unreactive, as the electrons in the molecule are already well-bonded and not likely to be easily transferred.
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The only thing you need to solve it is to know that
<span>density = mass or volumes
</span>It does't matter which mass do you have- density is always the same, therefore <span> 13.6 g/cm^3</span>×10
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chemical changes or chemical reactions
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I think its the first one. unless there is more to the question