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Ronch [10]
3 years ago
12

How many mols of H3PO4 are produced when 284 g P4O10 reacts completely to form H3PO4? P4O10 + 6H2O --> 4H3PO4

Chemistry
1 answer:
LenKa [72]3 years ago
5 0

Answer:

4 moles of H3PO4

Explanation:

Molar mass of P4O10 = 284 g/mol

Number of moles of P4O10  reacted = 284g/284 g/mol = 1 mole of P4O10

From the reeaction equation;

1 mole of P4O10 yields 4 moles of H3PO4

Hence, 284 g of P4O10 yields 4 moles of H3PO4

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Answer:

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Explanation:

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P_2 = Final pressure = 113 kPa

V_1 = Initial volume = 350 mL

V_2 = Final volume

From the Boyle's law we have

P_1V_1=P_2V_2\\\Rightarrow V_2=\dfrac{P_1V_1}{P_2}\\\Rightarrow V_2=\dfrac{124.12\times 350}{113}\\\Rightarrow V_2=384.44\ \text{mL}=0.384\ \text{L}

The volume the gas would occupy is 0.384\ \text{L}.

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