I know water will change the shape to match the container its in if that is your question
Answer:

Explanation:
1. Moles of CCl₄

2. Molar mass of CCl₄
MM = 1 × 12.01 + 4 × 35.5 = 12.01 + 142 = 154.0 g/mol
3. Mass of CCl₄

4. Volume of CCl₄

Answer: 5.0 moles
Explanation:
From the equation, we see that for every 4 moles of ammonia consumed, 4 moles of nitrogen monoxide are produced (we can reduce this to moles of ammonia consumed = moles of nitrogen monoxide produced).
This means that the answer is <u>5.0 mol</u>
8.3mL
Explanation:
Given parameters:
Mass of acetone = 6.54g
Density of acetone = 0.7857 g/mL
Unknown:
Volume of acetone = ?
Solution:
Density is defined as the mass per unit volume of a substance. It is expressed mathematically as shown below:
Density = 
Since the unknown is volume, we make it the subject of the formula
Volume = 
Input the values;
Volume =
= 8.3mL
learn more:
Volume brainly.com/question/2690299
#learnwithBrainly
The answer is 6.88.
Solution:
We can calculate for the percent composition of CaCl2 by mass by dividing the mass of the CaCl2 solute by the mass of the solution and then multiply by 100. The total mass of the resulting solution is the sum of the mass of CaCl2 solute and the mass of water solvent. Therefore, the percent composition of CaCl2 by mass is
% by mass = (mass of the solute / mass of the solution)*100
= mass of solute / (mass of the solute + mass of the solvent)*100
= (27.7 g CaCl2 / 27.7g + 375g) * 100
= 6.88