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Ronch [10]
3 years ago
12

How many mols of H3PO4 are produced when 284 g P4O10 reacts completely to form H3PO4? P4O10 + 6H2O --> 4H3PO4

Chemistry
1 answer:
LenKa [72]3 years ago
5 0

Answer:

4 moles of H3PO4

Explanation:

Molar mass of P4O10 = 284 g/mol

Number of moles of P4O10  reacted = 284g/284 g/mol = 1 mole of P4O10

From the reeaction equation;

1 mole of P4O10 yields 4 moles of H3PO4

Hence, 284 g of P4O10 yields 4 moles of H3PO4

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b. The number of electrons

Explanation:

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2 years ago
What is the pH of a solution with a concentration of 1.8 × 10-4 molar H3O+?
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pH=-log[H^{+}]=-log[H_{3}O]

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8 0
3 years ago
5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure<br> water?
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Answer:

\boxed {\boxed {\sf 2.8 \ m }}

Explanation:

The formula for molality is:

m=\frac{moles \ of \ solute}{kg \ of \ solvent}

There are 0.210 moles of KBr and 0.075 kilograms of pure water.

moles= 0.210 \ mol \\kilograms = 0.075 \ kg

Substitute the values into the formula.

m= \frac{ 0.210 \ mol }{0.075 \ kg}

Divide.

m= 2.8 \ mol/kg= 2.8 \ m

The molality is <u>2.8 moles per kilogram</u>

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2 years ago
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