Am I the only one who cannot see the answers?? Does anybody know how to solve this?
1 answer:
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Answer:
The governing ratio for thin walled cylinders is 10 if you use the radius. So if you divide the cylinder´s radius by its thickness and your result is more than 10, then you can use the thin walled cylinder stress formulas, in other words:
- if
then you have a thin walled cylinder
or using the diameter:
- if
then you have a thin walled cylinder
Answer:
Temperature on the inside ofthe box
Explanation:
The power of the light bulb is the rate of heat conduction of the bulb,
The thickness of the wall, L = 1.2 cm = 0.012m
Length of the cube's side, x = 20cm = 0.2 m
The area of the cubical box, A = 6x²
A = 6 * 0.2² = 6 * 0.04
A = 0.24 m²
Temperature of the surrounding,
Temperature of the inside of the box,
Coefficient of thermal conductivity, k = 0.8 W/m-K
The formula for the rate of heat conduction is given by:
Answer:
the atomic radius of a lithium atom is 0.152 nm
Explanation:
Given data in question
structure = BCC
lattice constant (a) = 0.35092 nm
to find out
atomic radius of a lithium atom
solution
we know structure is BCC
for BCC radius formula is /4 × a
here we have known a value so we put a in radius formula
radius = /4 × a
radius = /4 × 0.35092
radius = 0.152 nm
so the atomic radius of a lithium atom is 0.152 nm