Question

A straight, vertical wire carries a current of 2.15 A downward in a region between the poles of a large superconducting electromagnet, where the magnetic field has a magnitude of B = 0.574 T and is horizontal.
a) What is the magnitude of the magnetic force on a 1.00 cm section of the wire that is in this uniform magnetic field, if the magnetic field direction is east?

b) What is the magnitude of the magnetic force on a 1.00 cm section of the wire that is in this uniform magnetic field, if the magnetic field direction is south?

c) What is the magnitude of the magnetic force on a 1.00 cm section of the wire that is in this uniform magnetic field, if the magnetic field direction is 30.0 degrees south of west?

d) What is the direction of this magnetic force?

Answer 1

Answer:

a) F = 0.01234N to the south direction

b) F = 0.01234N to the north direction

c) F = 0.01234N

d) North of West

Explanation:

The magnetic force in a magnetic field is given by:

$F = BIlsin \theta$

Length of the wire, l = 1 cm = 0.01 m

Current flowing through the wire, I = 2.15 A

a) If the magnetic field direction is east

∅ = 90

F = 0.574 * 2.15 * 0.01

F = 0.01234 N to the south direction according to the Fleming's Right Hand Rule

b) If the magnetic field direction is south

The magnitude of the magnetic force remains the same

That is , F = BIL sin 90

F = 0.01234 N to the west

c) If the magnetic field direction is 30 degrees south

The angle between the magnetic field and the length of the wire still remains 90 degrees

Therefore the magnitude of the force still remains 0.01234

F = 0.01234 N

d) the direction of the force is the North of West