A straight, vertical wire carries a current of 2.15 A downward in a region between the poles of a large superconducting electrom
1 answer:
Answer:
a) F = 0.01234N to the south direction
b) F = 0.01234N to the north direction
c) F = 0.01234N
d) North of West
Explanation:
The magnetic force in a magnetic field is given by:
Length of the wire, l = 1 cm = 0.01 m
Current flowing through the wire, I = 2.15 A
a) If the magnetic field direction is east
∅ = 90
F = 0.574 * 2.15 * 0.01
F = 0.01234 N to the south direction according to the Fleming's Right Hand Rule
b) If the magnetic field direction is south
The magnitude of the magnetic force remains the same
That is , F = BIL sin 90
F = 0.01234 N to the west
c) If the magnetic field direction is 30 degrees south
The angle between the magnetic field and the length of the wire still remains 90 degrees
Therefore the magnitude of the force still remains 0.01234
F = 0.01234 N
d) the direction of the force is the North of West
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B) The object's velocity doubled.
Explanation:
The graph is missing: find it in attachment.
The kinetic energy of an object is the energy possessed by the object due to its motion. It is calculated as
where
m is the mass of the object
v is the velocity of the object
We notice that:
- The kinetic energy is directly proportional to the mass
- The kinetic energy is proportional to the square of the velocity
In the graph, one of the two quantities (either mass or speed) is represented on the x-axis, while the quantity on the y-axis is the kinetic energy.
First of all, we notice that the relationship is not linear: this means that the quantity on the x-axis cannot be the mass, so it must be the velocity.
Moreover, we notice that when the quantity on the x-axis increases from 1 to 2 (so, it doubles), the kinetic energy increases by a factor of 4. This means that the object's velocity has doubled, therefore
B) The object's velocity doubled.
Learn more about kinetic energy:
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