Answer: The person will still have a mass of 90kg on Mars
Explanation: The Truth is, the mass of a body remains constant from place to place. It is the weight which is equal to {mass of body * acceleration due to gravity{g}} that varies from place to place since it is dependent on {g}.
In this case the person will have a Weight of 90*9.8 = 882N on Earth.
{ "g" on Earth is 9.8m/s²}
And a Weight of 90*3.3 = 297N on Mars.
{ From the question "g" on Mars is {9.8m/s²}/3 which is 3.3m/s²}
From this analysis you notice that the WEIGHT of the person Varies but the MASS remained Constant at 90kg.
Answer:
Respuesta correcta, opción D: Es la fuerza que un cuerpo ejerce perpendicularmente sobre el área en la que actúa.
Explanation:
La definición de presión es la fuerza que un cuerpo ejerce en dirección perpendicular sobre el área en la que actúa.
Cuando se aplica una fuerza sobre la superficie de un cuerpo, la presión es la siguiente:

En donde:
F es la fuerza aplicada.
A es el área del cuerpo.
Por lo tanto la opción correcta es la D: es la fuerza que un cuerpo ejerce perpendicularmente sobre el área en la que actúa.
Espero que se sea de utilidad!
The ration of the rms speed of 235uf6 to that of 238uf6 is 1.004.
The molecular mass of 235uf6 is 349, while that of 238uf6 is 352.
The rms speed is calculated as
v=√(3RT/m)
Thus the ratio rms speed of 235uf6 to 238uf6 is calculated as
r=√(352/349)=1.004
Answer:

Explanation:
In this question we have given

we have to find

We know that
optical path difference for bright fringe is given as
Here,
n is order of fringe
and optical path difference for dark fringe is given as
since the light with wavelength
produces its third-order bright fringe at the same place where the light with wavelength
produces its fourth dark fringe
it means
optical path difference for 3rd order bright fringe= optical path difference for forth order dark fringe
Therefore,
...............(1)
Put value of
in equation (1)



Answer:
5p
Explanation:
We are given that a tin has 50 electrons.
We have to find in which subshell electrons experience the lowest effective nuclear charge.
We know that the electron in outermost shell experience the lowest effective nuclear charge.
Electronic configuration is given by

Outer most sub-shell is 5p. Therefore, 5p subshell experience the lowest effective nuclear charge because the distance of 5p sub-shell is large from nucleus.
Answer: 5p