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Illusion [34]
3 years ago
13

Analysis of 20.0 g of a compound containing only calcium and bromine indicates that 4.00 g of calcium are present. What is the e

mpirical formula of the compound formed?
A. Ca7Br2
B. Ca3Br2
C. CaBr2
D. Ca5Br2
Chemistry
1 answer:
Leto [7]3 years ago
3 0

Answer:

d. Ca_5Br_2

Explanation:

Mass of calcium = 4.00 g

Molar mass of calcium = 40.078 g/mol

<u>Moles of calcium = 4.00 / 40.078 moles = 0.9981 moles</u>

Given that the compound only contains calcium and bromine. So,

Mass of bromine in the sample = Total mass - Mass of calcium

Mass of the sample = 20.0 g

<u>Mass of bromine in sample = 20.0 - 4.00 g = 16.0 g</u>

Molar mass of bromine = 79.904 g/mol

<u>Moles of Bromine  = 16.0 / 79.904  = 0.2002 moles </u>

Taking the simplest ratio for Ca and Br as:

0.9981 : 0.2002  = 5 : 1

The empirical formula is = Ca_5Br_2

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From the balanced reaction we conclude that

As, 2 mole of O_2 react with 1 mole of CH_4

So, 5 moles of O_2 react with \frac{5}{2}=2.5 moles of CH_4

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A container of N, 03(9) has a pressure of 0.490 atm. When the absolute temperature of the N, O2(g) is tripled, the gas
spayn [35]

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1 year ago
We make a basic solution by mixing 50. mL of 0.10 M NaOH and 50. mL of 0.10 M Ca(OH)2. It requires 250 mL of an HCl solution to
andreyandreev [35.5K]

<u>Answer:</u> The correct answer is Option 5.

<u>Explanation:</u>

  • To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of the NaOH.

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of the Ca(OH)_2

We are given:

n_1=1\\M_1=0.10M\\V_1=50mL\\n_2=2\\M_2=0.1\\V_2=50mL  

Putting all the values in above equation, we get:

M=\frac{(1\times 0.1\times 50)+(2\times 0.1\times 50)}{50+50}\\\\M=0.15M

  • To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base.

We are given:

n_1=1\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.15M\\V_2=100mL

Putting values in above equation, we get:

1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M

Hence, the correct answer is Option 5.

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3 years ago
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