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Illusion [34]
3 years ago
13

Analysis of 20.0 g of a compound containing only calcium and bromine indicates that 4.00 g of calcium are present. What is the e

mpirical formula of the compound formed?
A. Ca7Br2
B. Ca3Br2
C. CaBr2
D. Ca5Br2
Chemistry
1 answer:
Leto [7]3 years ago
3 0

Answer:

d. Ca_5Br_2

Explanation:

Mass of calcium = 4.00 g

Molar mass of calcium = 40.078 g/mol

<u>Moles of calcium = 4.00 / 40.078 moles = 0.9981 moles</u>

Given that the compound only contains calcium and bromine. So,

Mass of bromine in the sample = Total mass - Mass of calcium

Mass of the sample = 20.0 g

<u>Mass of bromine in sample = 20.0 - 4.00 g = 16.0 g</u>

Molar mass of bromine = 79.904 g/mol

<u>Moles of Bromine  = 16.0 / 79.904  = 0.2002 moles </u>

Taking the simplest ratio for Ca and Br as:

0.9981 : 0.2002  = 5 : 1

The empirical formula is = Ca_5Br_2

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<u>Explanation:</u>

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where,

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n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

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Putting values in above equation, we get:

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