- The complexity of Earth is beyond the capabilities of computer simulations.
- Numerous assumptions that must be made by computer models have a big impact on the forecasts they produce.
- A computer model can incorporate historical climate data, but it is not possible to draw assumptions about future climates using this data in any way.
- A computer model cannot distinguish between anthropogenic climate change and natural climatic fluctuations.
<h3>How precise are temperature forecasts made by climate models?</h3>
The forecasting of global surface temperatures is one of the most significant results of climate models.
Scientists evaluate the effectiveness of their models by contrasting observations of the Earth's climate with predictions of future temperatures and "hindcasts" of past temperatures. Then, by comparing specific climate models and the average of all models to actual warming, scientists may determine whether temperature projections are accurate.
Researchers can have more faith that models can effectively predict future changes in the same factors if they successfully simulate the climate response in the past.
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Answer:
Atoms in a element on the periodic table I dont know which one tho so try google that sorry I am not much of a help
Explanation:
Gravitational Potential Energy, GPE = mgh
Where m is your mass in kg, g is acceleration due to gravity = 9.8 m/s², and h is the height in m.
The only value that be controlled here is the height h. The mass is constant, and acceleration due to gravity at that place is constant.
But h can be varied.
Hence to increase the gravitational potential energy between yourself and Earth is to increase the height h.
This can be done by climbing up a table, or climbing up a building through the stairs, or by using a lift.
F = G mM / r^2, where
<span>F = gravitational force between the earth and the moon, </span>
<span>G = Universal gravitational constant = 6.67 x 10^(-11) Nm^2/(kg)^2, </span>
<span>m = mass of the moon = 7.36 × 10^(22) kg </span>
<span>M = mass of the earth = 5.9742 × 10^(24) and </span>
<span>r = distance between the earth and the moon = 384,402 km </span>
<span>F </span>
<span>= 6.67 x 10^(-11) * (7.36 × 10^(22) * 5.9742 × 10^(24) / (384,402 )^2 </span>
<span>= 1.985 x 10^(26) N</span>
Answer:
is the compression in the spring
Explanation:
Given:
- mass of the bullet,
- mass of block,
- stiffness constant of the spring,
- initial velocity of the spring just before it hits the block,
<u>Now since the bullet-mass gets embed into the block, we apply the conservation of momentum as:</u>
Now this kinetic energy of the combined mass gets converted into potential energy of the spring.
is the compression in the spring
