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3 years ago

11

A 1,500-kg car accelerates along a flat track to a speed of 20 m/s. how much does it's gravitational potential energy increases

over the length of the track?

1 answer:

lesya [120]3 years ago

3 0

Look at bitesizes physics section, they have all the information you need to complete this question.

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Two point charges are brought closer together, increasing the force between them by a factor of 17. By what factor was their sep

nignag [31]

Answer:

$\dfrac{r_1}{r_2}=4.123$

Explanation:

Given:

Final force between them=17(initial force between them)

initial separation between them $r_1$

Final separation between them $r_2$

Let Q and q be the charges on them then

$F_2=17F_1\\\dfrac{kQq}{r_2^2}=17\dfrac{kQq}{r_1^2}\\\dfrac{r_1^2}{r_2^2}=17\\\dfrac{r_1}{r_2}=4.123$

6 0

3 years ago

surface is tipped to all principal planes of projection. Because it is not perpendicular to any projection plane, it cannot appe

Aleksandr [31]

Answer:

Oblique surface

Explanation:

Surfaces or lines situated at an angle in relation to all the main projection planes are oblique. An oblique surface never appears in any of the main perspectives as a line or true size area. It's Tipped to all main projection planes. doesn't quite appear on the edge of every standard view. doesn't quite show up in any view in true size.it has always been foreshortened.

7 0

4 years ago

{WORTH BRAINLIEST WITH AN EXPLANATION} Janine is a police officer patrolling a street. She drives 2.2 km east, then 4.4 km west,

icang [17]

Answer:

Options (3) and (6)

Explanation:

Janine drives 2.2 km East.

Since, distances measured in the East are positive,

Displacement = 2.2 km

Then she drives 4.4 km west

Displacement = -4.4 km

Followed by 1.7 km in the East

Displacement = 1.7 km

Total displacement = 2.2 - 4.4 + 1.7 = -0.5 km

$\overrightarrow{d}=-0.5$ km

Total distance covered by Janine = 2.2 + 4.4 + 1.7 = 8.3 km

d = 8.3 km

Therefore, Options (3) and (6) will be the answer.

5 0

4 years ago

A heavy frog and a light frog jump straight up into the air. They push off in such away that they both have the same kinetic ene

Ilia_Sergeevich [38]

Answer:

The lighter frog goes higher than the heavier frog.

The lighter frog is moving faster than the heavier frog

Explanation:

If both frogs have the same kinetic energy when they leave the ground, the following equality applies:

$K(light) = K(heavy) = \frac{1}{2} *ml*vol^{2} = \frac{1}{2}*mh*voh^{2}$

Now, if the only force acting on the frogs is gravity, when they reach to the maximum height, we can apply the following kinematic equation:

$vf^{2} -vo^{2} = 2*a*hmax = vf^{2} -vo^{2} = 2*(-g)*hmax$

When h= hmax, the object comes momentarily to an stop, so vf =0

Solving for hmax:

$hmax =\frac{vo^{2} }{2*g}$

As the lighter frog, in order to have the same kinetic energy than the heavier one, has a greater initial velocity, it will go higher than the other.

As a consequence of both having the same kinetic energy, the lighter frog will be moving faster than the heavier frog.

5 0

3 years ago

HELPP!! what is not true about mitosis??

Andreyy89

Answer:

I think its A

Explanation:

7 0

4 years ago

Read 2 more answers