There are O-H bonds in H2O. They have the intramolecular force of polar covalent bond.
Answer is: an oxybromate compound is KBrO₄ (x = 4).
ω(Br) = 43.66% ÷ 100%.
ω(Br) = 0.4366; mass percentage of bromine.
If we take 100 grams of compound:
m(Br) = ω(Br) · 100 g.
m(Br) = 0.4366 · 100 g.
m(Br) = 43.66 g; mass of bromine.
n(Br) = m(Br) ÷ M(Br).
n(Br) = 43.66 g ÷ 79.9 g/mol,
n(Br) = 0.55 mol; amoun of bromine.
From chemical formula (KBrOₓ), amount of potassium is equal to amount of bromine: n(Br) = n(K).
m(K) = 0.55 mol · 39.1 g/mol.
m(K) = 21.365 g; mass of potassium in the compound.
m(O) = 100 g - 21.365 g - 43.66 g.
m(O) =34.97 g; mass of oxygen.
n(O) = 34.97 g ÷ 16 g/mol.
n(O) = 2.185 mol.
n(K) : n(Br) : n(O) = 0.55 mol : 0.55 mol : 2.185 mol /÷ 0.55 mol.
n(K) : n(Br) : n(O) = 1 : 1 : 4.
Answer:
0.1828g/cm³
Explanation:
density= mass÷volume
m= 12.6g
v= 4.1×4.1×4.1 = 68.921cm³
•
density= 12.6÷68.921 = 0.1828g/cm³
Answer:
Explanation:
The amine functional group is obtained by subsititution of one or more hydrogen atoms in the ammonia compound.
Ammonia is NH₃.
Then,
- by substituting one hydrogen you obtain R - NH₂.
- by substituting two hydrogens you obtain R' - NH - R''
- by subsituting the three hydrogens you obtain:
R'''
|
R' - N - R''
In this case, the three subsitutuents are silyl groups. The silyl group is derived form silane and is SiH₃. So, the tcompound <em>trisilylamine</em> is:
SiH₃
|
SiH₃ - N - SiH₃
Thus, you can count 3 hydrogen atoms for every silylgroup for a total of <u><em>9 hydrogen atoms in each molecule of trisilylamine.</em></u>
