The distance from the base of the building the rock will land is 26.4 m
<h3>Data obtained from the question </h3>
- Horizontal velocity (u) = 20 m/s
- Height (h) = 8.50 m
- Distance (s) =?
<h3>Determination of the time to reach the ground </h3>
- Height (h) = 8.50 m
- Acceleration due to gravity (g) = 9.8 m/s²
- Time (t) =?
h = ½gt²
8.5 = ½ × 9.8 × t²
8.5 = 4.9 × t²
Divide both side by 4.9
t² = 8.5 / 4.9
Take the square root of both side
t = √(8.5 / 4.9)
t = 1.32 s
<h3>How to determine the distance </h3>
- Horizontal velocity (u) = 20 m/s
- Time (t) = 1.32 s
- Distance (s) =?
s = ut
s = 20 × 1.32
s = 26.4 m
Learn more about motion under gravity:
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The last one. Opposites attract while similar ones repulse each other so all forces are pushing them apart
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