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2 years ago

How many electrons have been removed from a positively charged electroscope if it has a net charge of 1.6× 10−13 C?

Physics

2 answers:

Alexxx [7]2 years ago

6 0

Answer:

Tu mujhe banaye ga face dekh aapna mirror me

Paul [167]2 years ago

5 0

Answer:

iloveyouuuuuuuuuuuuuuu

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What is the torque τb about axis b due to the force f⃗ ? (b is the point at cartesian coordinates (0,b), located a distance b fr

yKpoI14uk [10]

Check the attached file for the solution.

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3 years ago

A force F with arrow= (5xî+ 4yĵ), where F with arrow is in newtons and x and y are in meters, acts on an object as the object mo

harkovskaia [24]

Answer:

w= 62.75 J

Explanation:

Given that

Force vector F= 5 x i + 4 y j

Space vector or displacement vector d= 5.01 i

We know that work (w)

w=∫ F.ds

w= ∫(5 x i + 4 y j) .dx ( only object is moving in x- direction)

$w=\int_{0}^{5.01}5xi.dxi$

$w=\int_{0}^{5.01}5x.dx$

$w=\left [\dfrac{5}{2}x^2\right ]_0^{5.01}$

w= 2.5 x 5.01² J

w= 62.75 J

6 0

3 years ago

How does inertia affect a person who is not wearing a seatbelt during a collision?

Rainbow [258]

An object in motion will stay in motion, therefore the person will still be going the same speed as the car was going before the collision

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3 years ago

A 0.335 kg mass is attached to a spring and executes simple harmonic motion with a period of 0.38 s. The total energy of the sys

kramer

Answer:

$k=91.54 \frac{N}{m}$

Explanation:

The angular speed is defined as the angle traveled in one revolution over the time taken to travel it, that is, the period. Therefore, it is given by:

$\omega=\frac{2\pi}{T}\\\omega=\frac{2\pi}{0.38s}\\\omega=16.53\frac{rad}{s}$

The angular frequency of the simple harmonic motion of the mass-spring system is defined as follows:

$\omega=\sqrt{\frac{k}{m}}$

Here, k is the spring's constant and m is the mass of the body attached to the spring. Solving for k:

$\omega^2=\frac{k}{m}\\k=m\omega^2\\k=0.335kg(16.53\frac{rad}{s})^2\\k=91.54 \frac{N}{m}$

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3 years ago

Which describes how to generate a real image of an object using a concave mirror?

Naddika [18.5K]

A concave mirror is curved inward in the middle, more like a cave. Because the mirror is curved inward, the angle of the light surface can be focused similar to that of the camera. They can form real images that are projected out in front of the mirror at the place where light focuses. When the object is located at the center of the curvature the image formed will also be at the curvature. The image will be inverted and the magnification value is equal to 1 which will become a real image because the ray of light converges at the location of the formed image.

7 0

3 years ago

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