Answer:
Explanation:
F=ma
F in this case is the gravity acting on the 2kg object. Acceleration of gravity is 9.8 m/s^2. SF=ma, so
F = 2kg*(9.8 m/s^2) = 19.6 N
Now use this force to determine the mass of the object on the table:
F=ma
19.6 N (1N=kg*m/s^2) = m*(1.8 m/s^2)
m = 10.89 kg
Answer:
The force needed to slow down the car is, F = 67.5 N
Explanation:
Given data,
The mass of the car, m = 15 kg
The initial velocity of the car, V = 60 m/s
The final velocity of the car, v = 15 m/s
The time period of deceleration, t = 10 s
The difference in the momentum of the car is,
mV - mv = 15(60 - 15)
= 675 kg m/s
The rate of change in momentum of the car gives the force acting on it.
F = (mV - mu) / t
Substituting the values,
F = 675 / 10
= 67.5 N
Hence, the force needed to slow down the car is, F = 67.5 N
How dense the medium is in the compression part of the wave and how rare the medium is in the rarefaction part of the wave is a measure of the longitudinal wave's amplitude.
An electric field has both magnitude and direction.
I don't think that's one of the first 3 choices.
Answer and Explanation:
Data provided as per the question is as follows
Speed at point A = 20 m/s
Acceleration at point C = 
The calculation of the magnitude of the acceleration at A is shown below:-
Centripetal acceleration is
now we will put the values into the above formula
= 
After solving the above equation we will get
Tangential acceleration is
