The answer is A. Hope this helps. :)
        
                    
             
        
        
        
If no other forces act on the object, according to Newton’s first law, the spacecraft will continue moving at a constant velocity, assuming that a planet or something with large mass doesn’t cross its path. Forces are not required to continue the motion of an object on a frictionless plane at a constant rate. 
 
        
                    
             
        
        
        
Answer:

Explanation:
given,
side slope = 1 : 1
hydraulic depth(y) = 5 ft
bottom width (b)= 8 ft
x = 1
Q = 2,312 ft³/s
n = 0.013 
slope of channel = ?



R = 4.69 m
using manning's equation



S = 0.406

 
        
             
        
        
        
Answer:
depende de que fenómenos nos referimos de acuerdo al los cuerpos de formación puede aver movimiento contante
 
        
             
        
        
        
Answer:
Vb = k Q / r        r <R
 Vb = k q / R³ (R² - r²)    r >R
Explanation:
The electic potential is defined by
              ΔV = - ∫ E .ds
We calculate the potential in the line of the electric pipe, therefore the scalar product reduces the algebraic product
              VB - VA = - ∫ E dr
Let's substitute every equation they give us and we find out
r> R
            Va = - ∫ (k Q / r²) dr
            -Va = - k Q (- 1 / r)
We evaluate with it Va = 0 for r = infinity
           Vb = k Q / r        r <R
          
We perform the calculation of the power with the expression of the electric field that they give us
            Vb = - int (kQ / R3 r) dr
   We integrate and evaluate from the starting point r = R to the final point r <R
          Vb = ∫kq / R³ r dr
          Vb = k q / R³ (R² - r²)
This is the electric field in the whole space, the places of interest are r = 0, r = R and r = infinity