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Hunter-Best [27]
3 years ago
11

A spherical balloon is being inflated and the radius of theballoon is increasing at a rate of 2 cm/s.(A) Express the radius (r)

of the balloon as a function of thetime (t).(B) If V is the volume of the balloon as a function of theradius, find Vor and interpret it.
Physics
1 answer:
goblinko [34]3 years ago
6 0

Answer:

A.) r = 2t

B.) V = 33.5t^3

Explanation:

Given that a spherical balloon is being inflated and the radius of the balloon is increasing at a rate of 2 cm/s

A) Express the radius (r) of the balloon as a function of the time (t).

Since the rate = 2 cm/s that is,

Rate = radius/ time

Therefore,

2 = r/t

Make r the subject of formula

r = 2t

(B) If V is the volume of the balloon as a function of the radius, find V or and interpret it.

Let assume that the balloon is spherical. Volume of a sphere is;

V = 4/3πr^3

Substitute r = 2t into the formula

V = 4/3π(2t)^3

V = 4/3π × 8t^3

V = 32/3 × πt^3

V = 33.5t^3

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BaLLatris [955]

Answer:

The distance traveled by the skier is 5.309 km

Solution:

As per the question:

Mass of the skier, m = 64 kg

Coefficient of friction between the ski and the snow, \mu_{k} = 0.50

Mass of snow, M = 5.0 kg

Now,

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We know that:

f = \mu_{k}N

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N = Normal Reaction

N = mg

Thus

f = \mu_{k}mg                           (1)

Also,

fs = ML_{f}                                  (2)  

where

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Thus from eqn (1) and (2):

s = \frac{ML_{f}}{\mu_{k}mg}

s = \frac{5\times 3.33\times 10^{5}}{0.50\times 64\times 9.8}

s = 5.309 km

5 0
3 years ago
Which property of sound waves decreases as the square of the distance from the source increases?
Vitek1552 [10]

Answer:

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Explanation:

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4\pi r^2 is the area of the spherical surface

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As we see from the formula, the intensity is inversely proportional to the square of the distance from the source:

I\propto \frac{1}{r^2}

so, intensity is the correct answer.

3 0
3 years ago
If force remains constant and acceleration decreases what must happen to the mass
blondinia [14]

That can only be happening if the mass mysteriously increased somehow.  I'd like to know how in the world THAT happened.

4 0
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Phantasy [73]

Answer:

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Explanation:

Given that Speed and Motion you went from the starting line to the finish line at different rates.

If you repeated the activity while carrying weights but keeping your times the same, the weight carried will add up to the mass of the body.

And since Kinetic energy K.E = 1/2mv^2

Increase in the mass of the body will definitely make the kinetic energy of the body to increase.

Since the time is the same, that means the speed V is the same.

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The new kinetic energy will be:

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3 years ago
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Arada [10]

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It's more efficient (I'll edit later)

4 0
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