A spherical balloon is being inflated and the radius of theballoon is increasing at a rate of 2 cm/s.(A) Express the radius (r)
1 answer:
You might be interested in
Answer:
<em>Height = 5.65 km</em>
Explanation:
is the circumference or we can say measures the boundary of hemisphere of friction-less ice that he is sitting on.
So, the height will be = 2 x 3.14 x (30)^2 = 5654.7 m = 5.65 km
Answer:
a) F = 2.66 10⁴ N, b) h = 1.55 m
Explanation:
For this fluid exercise we use that the pressure at the tap point is
Exterior
P₂ = P₀ = 1.01 105 Pa
inside
P₁ = P₀ + ρ g h
the liquid is water with a density of ρ=1000 km / m³
P₁ = 0.85 1.01 10⁵ + 1000 9.8 5
P₁ = 85850 + 49000
P₁ = 1.3485 10⁵ Pa
the net force is
ΔP = P₁- P₂
Δp = 1.3485 10⁵ - 1.01 10⁵
ΔP = 3.385 10⁴ Pa
Let's use the definition of pressure
P = Fe / A
F = P A
the area of a circle is
A = pi r² = [i d ^ 2/4
let's reduce the units to the SI system
d = 100 cm (1 m / 100 cm) = 1 m
F = 3.385 104 pi / 4 (1) ²
F = 2.66 10⁴ N
b) the height for which the pressures are in equilibrium is
P₁ = P₂
0.85 P₀ + ρ g h = P₀
h =
h =
h = 1.55 m
First we need to convert the angular speed from rpm to rad/s. Keeping in mind that
the angular speed is
And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion:
the angular speed is
And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion: