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Veseljchak [2.6K]
4 years ago
15

Round off 4.5778 x 10mg to three significant figures.

Chemistry
1 answer:
lakkis [162]4 years ago
4 0

Answer:

Explanation:

= 45.8

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When Z-4,5-dimethyloct-4-ene is treated with hydrogen chloride, HCl, the result is:________.
Vika [28.1K]

Answer:

The  correct option is  c

Explanation:

The chemical equation for the reaction of  Z-4,5-dimethyloct-4-ene and HCl is shown on the first uploaded image

Now looking at the product we see that there are two who has four different groups attached to them this carbon are known as chiral carbons hence the product formed is a pair of diastereomers

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4 years ago
If you have 177 grams of C4H80, how many moles do you have?
quester [9]
I think it’s 2.45, not 100% sure
4 0
3 years ago
The molecular formula of butane is C4H10. It is obtained from petroleum and is used commonly in LPG (Liquefied Petroleum Gas) cy
guajiro [1.7K]

Answer:

See attached picture.

Explanation:

Hello.

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7 0
3 years ago
What is a hypothesis?
krek1111 [17]

Answer:

The 4th option

a possible explanation of or answer to a scientific question

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4 0
3 years ago
Read 2 more answers
A. Calculations for the Determination of Ammonium Chloride The data from the data entry portion of the report has been copied in
Vladimir79 [104]

Answer:

A

Explanation:

Considering question A

Mass of  original sample is m_o = 0.945 \ g

Mass of   NH4Cl is  m_n = 0.116 \ g

Percent of  NH4Cl is k   =  12.275 \%

B

Mass of  NaCl  m_k  =  0.359 \ g

C

Mass  of  SiO2   m_e = 0.46

D

 Mass of original sample m_o = 0.945 \ g

  Differences in these weights (g) (use the absolute value of the difference)

recovery of matter   G  =   0.01 \ g

The  correct option is C

From the question we are told that

The mass of evaporating dish on #1 is  m_1 =  38.646 \ g

 The mass of evaporating dish and original sample   m_2 =  39 591 \ g

  The mass of evaporating dish after subliming NH_4Cl is m_3 =  39.4750 \  g

Generally the mass of the original sample is  mathematically represented as

        m_o =  m_2 - m_1

=>     m_o =  39 591 -  38.646

=>     m_o = 0.945 \ g

Generally the mass of NH_4Cl is mathematically represented as

        m_n = m_2 - m_3

=>      m_n = 39 591 - 39.4750

=>      m_n = 0.116 \ g

The  Percent  NaH_4 Cl (g)

        k   =  \frac{ m_n}{m_o} *100

=>     k   =  \frac{0.116 }{0.945} *100

=>      k   =  12.275 \%

Considering question B

The  mass of evaporating dish #2 is  m_g  =  38700\  g

The  mass of  watch glass is   m_a  =  28 299 \  g

The mass of evaporating dish #2, watch glass and NaCl  m_b  =  67,355 \  g

Generally the mass of NaCl is  

       m_k  =  m_b -[m_g + m_a]

=>     m_k  =  67,355  -[38700 + 28 299]

=>      m_k  =  0.359 \ g

Considering question C

 The mass of evaporating dish is   m_p= 38.645

 The mass of evaporating dish and SiO2     m_s  = 39.105 \ g

Generally  the mass of  SiO2  is  mathematically represented as

        m_e = 39.105 - 38.645

=>      m_e = 0.46

Considering  D

The  mass of the original  sample  is  m_o  =  0.945 \  g

Generally the experimental  mass recovered (NH_4Cl,NaCl, SiO2 ) is mathematically evaluated as

     M =0.116 + 0.46 + 0.359

    M  =  0.935 \ g

Generally the differences in these weights (g) of recovery of matter is mathematically represented as.

     G  =0.945- 0.935

=>   G  =   0.01 \ g

While drying the NaCl, the liquid boiled and some splattered out of the evaporating dish, causing the recovered mass to be lower.

     

6 0
3 years ago
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