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Alex
3 years ago
13

A solution contains 3.75 g of a nonvolatile pure hydrocarbon in 95 g acetone. The boiling point of pure acetone is 55.95°C and o

f the solution is 56.50°C. The Kb for acetone is 1.71°C/m. What is the molar mass of the hydrocarbon?
Physics
1 answer:
Nimfa-mama [501]3 years ago
5 0

Answer: The molar mass of the hydrocarbon is 37 g/mol

Explanation:

Elevation in boiling point is given by:

\Delta T_b=i\times K_b\times m

\Delta T_b=T_b-T_b^0=(56.50-55.95)^0C=0.55^0C = Elevation in boiling point

i= vant hoff factor =1  (for non electrolyte )

K_b = boiling point constant = 0.512^0C/m

m= molality

\Delta T_b=i\times K_b\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (acetone) = 95 g = 0.095 kg

Molar mass of solute = M g/mol

Mass of solute = 3.75 g

0.55^0C=1\times 0.512\times \frac{3.75g}{Mg/mol\times 0.095kg}

M=37g/mol

Thus the molar mass of the hydrocarbon is 37 g/mol

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5 0
3 years ago
Read 2 more answers
A tow truck drags a stalled car along a road. The chain makes an angle of 30° with the road and the tension in the chain is 1400
AURORKA [14]

Answer:

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Explanation:

Work is defined as the force that is applied on a body to move it from one point to another. When a force is applied, an energy transfer occurs. Then it can be said that work is energy in motion.

So work is one of the forms of energy transmission between bodies. To perform a job, you must exert a force on a body and it moves.

In the International System of Units, work is measured in Joule. A Joule is the work that a constant force of 1 Newton does on a body that moves 1 meter in the same direction and direction as the force. Then, Joule is equivalent to Newton per meter.

The work is equal to the product of the force by the distance and by the cosine of the angle that exists between the direction of the force and the direction that travels the point or the object that moves:

Work= Force*Distante* cos (θ)

In this case:

  • Force= 1,400 N= 1,400 kg*\frac{m}{s^{2} }
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Replacing:

Work= 1,400 N* 1,000 m* cos (30°)

Work= 1,212,435. 565 Joule≅ 1,212,436 J

<u><em> The work is done by the truck pulling the car 1 km is 1,212,436 J</em></u>

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3 years ago
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Answer:

the distance between the particles and also the amount of electric charge they carry.

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8 0
2 years ago
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