There is no right or wrong answer, your teacher wants you to support your own answer with points. As long as the reasons make logical sense you are fine.
I think they both have valid points. Their replies are both true, but from a buyer's perspective who would you purchase services from? You would get different answers depending on who you ask.
If you choose to go old school, obviously you get an actual photo that can be stored physically. This means it is a memory that can be preserved, and it might feel more nostalgic being able to touch the photo.
On the other hand, a digitally stored photo can be altered (photoshop), but it is forever as long as the internet still exists. A physical photo would fade with time, which doesn't happen with a digital photo.
It is definitely easier to argue that digital photography has more advantages (they do, it is why nobody uses film anymore)
Points you can consider:
Can be transferred to the other side of the world instantly
Ability to make copies and print as many photos as you want
Can be stored on cloud/devices and be like that forever
Compare them with film photography to give a more solid response.
Explanation:
here u = 50m/s
v = 60m/s
t = 58 s
then a = (60-50)/58 m/s2
= 0.17m/s2
now s= ut+1/2at2
so , 50×58+0.5×0.17×(58)^2 m
= 3185.94 m
= 3.18 km
Answer:
El material del calorímetro es aislante, conducción térmica entre sustancias y alrededores casi nula.
Explanation:
Es posible suponer que la energía térmica que gana el agua en un calórimetro equivale a la energía térmica perdida por la muestra que se prueba, en tanto que el material del calorímetro se caracteriza por ser de naturaleza aislante, es decir, que no permite las interacciones de energía entre los fluidos al interior y los alrededores del calorímetro.
Answer:
3.31m/s
Explanation:
Angular momentum for 3s is
![L = L_i_n_i + L_3_s](https://tex.z-dn.net/?f=L%20%3D%20L_i_n_i%20%2B%20L_3_s)
![L = 2(11.5kg) + \int\limits^ {3s}_ {0s} {(t^2 + 2)} \, dt](https://tex.z-dn.net/?f=L%20%3D%202%2811.5kg%29%20%2B%20%5Cint%5Climits%5E%20%7B3s%7D_%20%7B0s%7D%20%7B%28t%5E2%20%2B%202%29%7D%20%5C%2C%20dt)
![L = 23kg+(\frac{t^3}{3} +2t)^ {3s}_ {0s}\\\\L=38kgm/s](https://tex.z-dn.net/?f=L%20%3D%2023kg%2B%28%5Cfrac%7Bt%5E3%7D%7B3%7D%20%2B2t%29%5E%20%7B3s%7D_%20%7B0s%7D%5C%5C%5C%5CL%3D38kgm%2Fs)
Moment if inertia is
![I = 2ml^2](https://tex.z-dn.net/?f=I%20%3D%202ml%5E2)
![I = 2(11.5)(0.5)^2\\\\I=5.75kgm^2](https://tex.z-dn.net/?f=I%20%3D%202%2811.5%29%280.5%29%5E2%5C%5C%5C%5CI%3D5.75kgm%5E2)
Angular speed
ω = L/I
![= 38 / 5.75\\\\=6.61](https://tex.z-dn.net/?f=%3D%2038%20%2F%205.75%5C%5C%5C%5C%3D6.61)
The speed of each ball is
V = ωL
![= 6.61\times0.5\\\\= 3.31m/s](https://tex.z-dn.net/?f=%3D%206.61%5Ctimes0.5%5C%5C%5C%5C%3D%203.31m%2Fs)