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3 years ago

What is the average acceleration of a car that starts from

Physics

2 answers:

MAXImum [283]3 years ago

4 0

Answer:

1.5m/s^2

Explanation:

In the picture above.

mr Goodwill [35]3 years ago

4 0

<u>Answer:</u>

The car is moving at an average acceleration of 1.5 m/s2

<u>Explanation</u>:

According to the question,

The car is moving in a straight road

The speed of the car = 18 m/s

Time is given (t) = 12 s

Acceleration is the rate of change of speed with respect to time. It is computed by the formula;

$\text { Acceleration }=\frac{\text {Speed }}{\text {Time}}$

Acceleration = (18 m/s)/(12 s)= 1.5 m/s2

$\text { Acceleration }=\frac{18 \mathrm{m} / \mathrm{s}}{12 \mathrm{s}}=1.5 \mathrm{m} / \mathrm{s}^{2}$

Therefore, the car is moving at an average acceleration of 1.5 m/s2

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Even though this region is gaseous, it is regarded as the Sun’s surface because at this point, light from the Sun is finally abl

galina1969 [7]

C- escape into the solar system, because the sun is neither a solid nor a liquid, and the sun already creates its warm temperature from many reactions. the light from the sun can scatter throughout the universe, eventually getting to earth. do, have you ever heard of a wave of light being referred to as a solid or a liquid?

7 0

2 years ago

A skater is using very low friction rollerblades. A friend throws a Frisbee at her, on the straight line along which she is coas

kupik [55]

Answer:

a) perfectly inelastic, b) collision is inelastic, c) elastic

Explanation:

In this exercise, it is asked to identify what type of shock occurs between the skater and the frisbee, for this we must define a system formed by the skater and the fribee, so that the forces during the crash have been internal and the amount of movement is preserved

Initial instant. Before the skater touches the frisbee

p₀ = M v₁ + m v₂

where M and m are the masses of the skater and frisbee, respectively

for the final moment they give us several possibilities, in all case the moment is conserved

p₀ = $p_{f}$

case a)

Final instant. grabs the frisbee and holds it

p_{f} = (M + m) v '

p₀ = p_{f}

We can see that this shock is perfectly inelastic, it holds the fressbee

case b)

final instant.

This case is similar to the previous one, but the final speed of fresbee is zero, therefore this collision is inelastic and the kinetic energy is not conserved.

case c)

final instant. Grab the fressbee and resend it

$p_{f} = M v_{1f} + m v_{2f}$

this is an elastic Shock since the equivalent of a rebound of the fressbee, the kinetic energy is conserved.

5 0

2 years ago

A 25,000 kg traveling east collides with a 2,000 kg truck standing still on the tracks. After the collision the train and truck

Elis [28]

Answer:

24.084 m/s

Explanation:

From the law of conservation of linear momentum

Total momentum before collision equals to the total momentum after collision

Since momentum=mv where m is mass and v is velocity

$M_{truck}V_{truck}=V_{common}*(M_{truck} +M_{standing})$ where $M_{truck}$ is the mass of the truck, $V_{truck}$ is velocity of the truck, $V_{common}$ is the common velocity of moving and standing truck after collision and $M_{standing}$ is the mass of the standing truck

Making $V_{truck}$ the subject we obtain

$V_{truck}=\frac { V_{common}*(M_{truck} +M_{standing})}{M_{truck}}$

Substituting $M_{truck}$ as 25000 Kg, $V_{common}$ as 22.3 m/s, $M_{standing}$ as 2000 Kg we obtain

$V_{truck}=\frac { 22.3 m/s *(25000 Kg +2000 Kg)}{25000}= 24.084 m/s$

Therefore, assuming no friction and considering that after collision they still move eastwards hence common velocity and initial truck velocities are positive

The truck was moving at 24.084 m/s

3 0

3 years ago

Carbon monoxide pure substance or mixture and why

trasher [3.6K]

Carbon monoxide is a mixture cause it's a mixture of
different chemical compounds

such as air and CO but they're chemically mixed together which makes it no longer pure

8 0

3 years ago

Read 2 more answers

Question 2 (1 point)

Tju [1.3M]

Answer:

I know someone anwsered but it would be 400M

Explanation:

i initial velocity (u)=10m/s

acceleration (a)=0

time taken (t) =40s

then distance (s)=u t +1/2 a t^2

s= u t +0 (as a is 0)

s= 10 x 40

s= 400M

7 0

3 years ago