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2 years ago

What is the average acceleration of a car that starts from

Physics

2 answers:

MAXImum [283]2 years ago

4 0

Answer:

1.5m/s^2

Explanation:

In the picture above.

mr Goodwill [35]2 years ago

4 0

<u>Answer:</u>

The car is moving at an average acceleration of 1.5 m/s2

<u>Explanation</u>:

According to the question,

The car is moving in a straight road

The speed of the car = 18 m/s

Time is given (t) = 12 s

Acceleration is the rate of change of speed with respect to time. It is computed by the formula;

$\text { Acceleration }=\frac{\text {Speed }}{\text {Time}}$

Acceleration = (18 m/s)/(12 s)= 1.5 m/s2

$\text { Acceleration }=\frac{18 \mathrm{m} / \mathrm{s}}{12 \mathrm{s}}=1.5 \mathrm{m} / \mathrm{s}^{2}$

Therefore, the car is moving at an average acceleration of 1.5 m/s2

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Name the inertia in the following cases.

Bogdan [553]

Answer:

inertia of motion

Explanation:

it's because when a passenger is jumping from a bus his/her body is in motion after falling in a road he/she remains or tends to remain in the state of motion that is the reason

5 0

1 year ago

A 3-kg wheel with a radius of 35 cm is spinning in the horizontal plane about a vertical axis through its center at 800 rev/s. A

Kruka [31]

Answer:

$\omega_f = 585.37 \ rev/s$

Explanation:

given,

mass of wheel(M) = 3 Kg

radius(r) = 35 cm

revolution (ω_i)= 800 rev/s

mass (m)= 1.1 Kg

I_{wheel} = Mr²

when mass attached at the edge

I' = Mr² + mr²

using conservation of angular momentum

$I \omega_i = I' \omega_f$

$(Mr^2) \times 800 = ( M r^2 + m r^2) \omega_f$

$M\times 800 = ( M + m )\omega_f$

$3\times 800 = (3+1.1)\times \omega_f$

$2400 = (4.1)\times \omega_f$

$\omega_f = 585.37 \ rev/s$

3 0

3 years ago

can somebody help me answer this question? A car went from 110 m/s to 80 m/s in 20 seconds. What was the acceleration of the car

gogolik [260]

Answer:

-1.5m/s²

Explanation:

Acceleration can be thought of as [Change in Velocity]/[Change in time]. To find these changes, you simply subtract the initial quantity from the final quantity.

So for this question you have: