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stepladder [879]
3 years ago
12

What is the average acceleration of a car that starts from

Physics
2 answers:
MAXImum [283]3 years ago
4 0

Answer:

1.5m/s^2

Explanation:

In the picture above.

mr Goodwill [35]3 years ago
4 0

<u>Answer:</u>

The car is moving at an average acceleration of 1.5 m/s2

<u>Explanation</u>:

According to the question,

The car is moving in a straight road

The speed of the car = 18 m/s

Time is given (t) = 12 s

Acceleration is the rate of change of speed with respect to time. It is computed by the formula;

\text { Acceleration }=\frac{\text {Speed }}{\text {Time}}

Acceleration = (18 m/s)/(12 s)= 1.5 m/s2

\text { Acceleration }=\frac{18 \mathrm{m} / \mathrm{s}}{12 \mathrm{s}}=1.5 \mathrm{m} / \mathrm{s}^{2}

Therefore, the car is moving at an average acceleration of 1.5 m/s2

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An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary
Assoli18 [71]

Answer:

The tension in the cable when the craft was being lowered to the seafloor is 4700 N.

Explanation:

Given that,

When the craft was stationary, the tension in the cable was 6500 N.

When the craft was lowered or raised at a steady rate, the motion through the water added an 1800 N.

The drag force of 1800 N will act in the upward direction. As it was lowered or raised at a steady rate, so its acceleration is 0. As a result, net force is 0. So,

T + F = W

Here, T is tension

F = 1800 N

W = 6500 N

Tension becomes :

T=W-F\\\\T=6500-1800\\\\T=4700\ N

So, the tension in the cable when the craft was being lowered to the seafloor is 4700 N.

7 0
3 years ago
A student throws a rock horizontally off a 5.0 m tall building. The rock's initial speed is 6.0 m/s. How long will it take the r
Archy [21]

Answer:

The time taken by the rock to reach the ground is 0.569 seconds.

Explanation:

Given that,

A student throws a rock horizontally off a 5.0 m tall building, s = 5 m

The initial speed of the rock, u = 6 m/s

We need to find the time taken by the rock to reach the ground. Using second equation of motion to find it. We get :

s=ut+\dfrac{1}{2}gt^2\\\\5=6t+\dfrac{1}{2}\times 9.8t^2\\\\t=0.569\ seconds

So, the time taken by the rock to reach the ground is 0.569 seconds. Hence, this is the required solution.

5 0
3 years ago
Read 2 more answers
An object attached to a horizontal spring is oscillating back and forth along a frictionless surface. The maximum speed of the o
Sliva [168]

Answer:

t = 0.37 seconds

Explanation:

t = (1/4)T

Maximum acceleration is;

a_max = Aω²

In simple harmonic motion, we know that v_max = Aω

Thus, a_max = v_max•ω

ω = a_max/v_max

We know that Period is given by;

T = 2π/ω

From initially, t = (1/4)T so, T = 4t

Thus, 4t = 2π/(a_max/v_max)

t = (2π/4)(v_max/a_max)

We are given;

Maximum velocity;v_max = 1.47 m/s

Max acceleration;a_max =6.24 m/s²

Thus,

t = (2π/4)(1.47/6.24)

t = 0.37 seconds

8 0
3 years ago
A hollow cylinder of mass 2.00 kgkg, inner radius 0.100 mm, and outer radius 0.200 mm is free to rotate without friction around
kipiarov [429]

Answer: 2.86 m

Explanation:

To solve this question, we will use the law of conservation of kinetic and potential energy, which is given by the equation,

ΔPE(i) + ΔKE(i) = ΔPE(f) + ΔKE(f)

In this question, it is safe to say there is no kinetic energy in the initial state, and neither is there potential energy in the end, so we have

mgh + 0 = 0 + KE(f)

To calculate the final kinetic energy, we must consider the energy contributed by the Inertia, so that we then have

mgh = 1/2mv² + 1/2Iw²

To get the inertia of the bodies, we use the formula

I = [m(R1² + R2²) / 2]

I = [2(0.2² + 0.1²) / 2]

I = 0.04 + 0.01

I = 0.05 kgm²

Also, the angular velocity is given by

w = v / R2

w = 4 / (1/5)

w = 20 rad/s

If we then substitute these values in the equation we have,

0.5 * 9.8 * h = (1/2 * 0.5 * 4²) + (1/2 * 0.05 * 20²)

4.9h = 4 + 10

4.9h = 14

h = 14 / 4.9

h = 2.86 m

8 0
3 years ago
Read 2 more answers
Why is it that when riding in a car, you don't feel like you're moving?
UkoKoshka [18]

This may shock you:

We NEVER feel speed, velocity, or motion, as long as it's constant.

We only feel CHANGES in speed, velocity, or motion.

That means speeding up, slowing down, or changing direction.

As long as we're moving in a straight line at a constant speed, we don't feel anything.

6 0
3 years ago
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