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Sergeu [11.5K]
3 years ago
8

Simplify. 6+4(12−15)2 Enter your answer in the box.

Mathematics
2 answers:
xenn [34]3 years ago
7 0

....................

satela [25.4K]3 years ago
7 0

Answer:

42

Step-by-step explanation:

6+4(12-15)^2

Order Of Operations: Parantheses

6+4(-3)^2

Exponent next:

6+4(9)

Multiplication:

6+36

=42

Hope this helps :)

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Given the following sequence, find the 23rd term: 3, 5, 7, 9, 11, . . .
sashaice [31]

Answer:

B. 47

Step-by-step explanation:

The formula for an arithmetic sequence is

an = a1+d(n-1)

a1 =3   (it is the first term)

We can find the common difference by taking the second term and subtracting the first term

5-3 =2

d=2

n = the term number we are looking for

an = 3 + 2(n-1)

We are looking for the 23rd term so n=23

a23 = 3 +2(23-1)

      = 3 +2(22)

      = 3+44

      = 47

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3 years ago
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Heights in inches of several tomato plants : 16,18,18,20,17,10,18,17 mean absolute deviation :
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3 years ago
Find the exact values of sin(u/2) cos(u/2) and tan(u/2) given sin u=24/25 and pie/2 < u < pie
vlada-n [284]

Recall the double/half angle formulas:

\cos^2\dfrac x2=\dfrac{1+\cos x}2

\sin^2\dfrac x2=\dfrac{1-\cos x}2

We're given \sin u=\frac{24}{25}, and since u is between π/2 and π, we expect \cos u to be negative. So from the Pythagorean identity, we find

\sin^2u+\cos^2u=1\implies\cos u=-\sqrt{1-\sin^2u}=-\dfrac7{25}

Also, we know \frac u2 will fall between π/4 and π/2, so both \sin\frac u2 and \cos\frac u2 will be positive. Then we find

\cos\dfrac u2=\sqrt{\dfrac{1+\cos u}2}=\dfrac35

\sin\dfrac u2=\sqrt{\dfrac{1-\cos u}2}=\dfrac45

and it follows that

\tan\dfrac u2=\dfrac{\sin\frac u2}{\cos\frac u2}=\dfrac43

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4 years ago
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Mice21 [21]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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