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meriva
3 years ago
11

A substance has a mass of 360 g and a volume of 7.5 cm3. What is its density?

Chemistry
1 answer:
a_sh-v [17]3 years ago
7 0
D = g / cm³

Density = mass / volume

D = 360 g / 7.5 cm³

D = 48 g/cm³

answer D

hope this helps!
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A wave has a frequency of 3,5MHz and a wavelength of 85,5 m. What is the wave velocity through
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Answer:

velocity = 29925×10⁶ m/s

Explanation:

Given data:

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Velocity = ?

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MHz to Hz

35×10⁶ Hz

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<em>velocity = Wavelength × Frequency</em>

velocity = 855 m × 35×10⁶ Hz

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<u>Answer:</u> The percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

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Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{17}^{35}\textrm{Cl} isotope be 'x'. So, fractional abundance of _{17}^{37}\textrm{Cl} isotope will be '1 - x'

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Mass of _{17}^{35}\textrm{Cl} isotope = 35 amu

Fractional abundance of _{17}^{35}\textrm{Cl} isotope = x

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Mass of _{17}^{37}\textrm{Cl} isotope = 37 amu

Fractional abundance of _{17}^{37}\textrm{Cl} isotope = 1 - x

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Putting values in equation 1, we get:

35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775

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Percentage abundance of _{17}^{37}\textrm{Cl} isotope = (1-0.775)=0.225\times 100=22.5\%

Hence, the percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

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