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Ivahew [28]
2 years ago
5

If the threshold wavelength for copper is 2665 A, calculate the maximum kinetic energy of a photoelectron generated by ultraviol

et light of λ 2000 A. Compute the stopping potential.
Physics
1 answer:
Over [174]2 years ago
7 0

Answer:

K.E.=2.48\times 10^{-19}\ J

Explanation:

Using the expression for the photoelectric effect as:

E=h\nu_0+\frac {1}{2}\times m\times v^2

Also, E=\frac {h\times c}{\lambda}

\nu_0=\frac {c}{\lambda_0}

Applying the equation as:

\frac {h\times c}{\lambda}=\frac {hc}{\lambda_0}+\frac {1}{2}\times m\times v^2

Where,

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda is the wavelength of the light being bombarded

\lambda_0 is the threshold wavelength

\frac {1}{2}\times m\times v^2 is the kinetic energy of the electron emitted.

Given, \lambda=2000\ \dot{A}=2000\times 10^{-10}\ m

\lambda_0=2665\ \dot{A}=2665\times 10^{-10}\ m

Thus, applying values as:

\frac {6.626\times 10^{-34}\times 3\times 10^8}{2000\times 10^{-10}}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{2665\times 10^{-10}}+K.E.

K.E.=\frac {6.626\times 10^{-34}\times 3\times 10^8}{2000\times 10^{-10}}-\frac {6.626\times 10^{-34}\times 3\times 10^8}{2665\times 10^{-10}}

K.E.==\frac{19.878}{10^{16}\times \:2000}-\frac{19.878}{10^{16}\times \:2665}

K.E.=2.48\times 10^{-19}\ J

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Energy from the Sun arrives at the top of the Earth’s atmosphere with an intensity of 1.30kW/m21.30⁢kW/m2. How long does it take
vivado [14]

Answer:

T=1.384×10⁶seconds

Explanation:

Given data

p (Intensity)=1.30 kw/m²

E (Energy)=1.8×10⁹ J

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T (Time required)=?

Solution

E=PT   ................eq(i)

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3 0
3 years ago
Which of the following is most likely to be an observation made by a physiologist
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3 0
3 years ago
R,=4.00 R, = 1000.00
lisabon 2012 [21]

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Explanation:

6 0
2 years ago
A man is dragging a trunk up the loading ramp of a mover’s truck. The ramp has a slope angle of 20.0°, and the man pulls upward
AleksandrR [38]

Answer:

(a)  104 N

(b) 52 N

Explanation:

Given Data

Angle of inclination of the ramp: 20°

F makes an angle of 30° with the ramp

The component of F parallel to the ramp is Fx = 90 N.  

The component of F perpendicular to the ramp is Fy.

(a)  

Let the +x-direction be up the incline and the +y-direction by the perpendicular to the surface of the incline.  

Resolve F into its x-component from Pythagorean theorem:  

Fx=Fcos30°

Solve for F:  

F= Fx/cos30°  

Substitute for Fx from given data:  

Fx=90 N/cos30°

   =104 N

(b) Resolve r into its y-component from Pythagorean theorem:

     Fy = Fsin 30°

   Substitute for F from part (a):

     Fy = (104 N) (sin 30°)  

          = 52 N  

5 0
2 years ago
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