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umka21 [38]
3 years ago
6

A cylindrical tank is 50 inches long, has a diameter of 16 inches and contains 1.65 lbm of water. Calculate the density of water

in Ibm per cubic feet.
Engineering
1 answer:
CaHeK987 [17]3 years ago
8 0

Answer:

<em>0.285 lbm per cubic feet</em>

<em></em>

Explanation:

length of tank = 50 inches = 50/12 feet = 4.17 feet

diameter of tank = 16 inches = 16/12 feet = 1.33 feet

weight of water = 1.65 lbm

density of water = ?

We know that the density of a substance is given as

ρ = w/v

where ρ is the density in Ibm per cubic feet

w is the weight in lbm

v is the volume in cubic feet

Volume of a cylinder = \frac{\pi d^{2} l}{4}

where d is the diameter

l is the length

volume = \frac{3.142*1.33^{2}* 4.17}{4} = 5.79 cubic feet

Therefore, the density of water will be

ρ = w/v = 1.65/5.79 = <em>0.285 lbm per cubic feet</em>

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int currentValue;

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this.currentValue = currentValue - value;

return currentValue;

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this.currentValue = currentValue * value;

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3 0
2 years ago
Consider tests of an unswept wing that spans the wind tunnel and whose airfoil section is NACA 23012. Since the wing model spans
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Answer:

Check the explanation

Explanation:

to know the lift per unit span (N/m) that is expected to be measured when the wing attack angle is 4°

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Kindly check the attached image below to see the step by step explanation to the above question.

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3 years ago
The lattice constant of a simple cubic primitive cell is 5.28 Å. Determine the distancebetween the nearest parallel ( a ) (100),
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Answer:

a)5.28 Å , b)3.73 Å , c)3.048 Å

Explanation:

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Therefore, a particular unit cell consist only 1/8th part of an atom.

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3 years ago
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Note: Kindly find an attached copy of the diagram associated with the solution to the question below.

Sources: the diagram to this question was researched from Quizlet

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Solution

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